There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
6x + 2 = 14 The solution: 6x + 2 = 14 6x +2 - 2 = 14 - 2 6x = 12 6x / 6 = 12 / 6 x = 2
19 - 2*7 + 98/14 = 12.
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
2x - 14 = -2, adding 14 to each side gives 2x = 14 - 2 = 12, dividing each side by 2 gives x = 12/2 Thus x = 6
To make a 2% sodium hypochlorite solution from a 12% solution, you can set up the equation: 12% solution * x litres = 2% solution * 100 litres Solving for x, you get: x = (2% solution * 100 litres) / 12% = 16.67 litres Therefore, you would need 16.67 litres of the 12% sodium hypochlorite solution to make 100 litres of a 2% solution.
There is no solution to: 4(2x + 2) + 12 > 1004(2x + 2) + 12 > 100 For 4(2x + 2) + 12 > 1004(2x + 2) + 12 to have a solution x < -1 which makes 1004(2x + 2) + 12 < 12, BUT 1004(2x + 2) + 12 is supposed to be greater than 100. Perhaps there is a missing operator in the digits of 1004?
-2
The solution to 12-4 to the 2 power, divided by 2 is equal to 4.
Solution 1: 3/4x + 2 = 12 x = [(12 - 2) * 4] / 3 x = 40/3 or 13.33 Solution 2: 0.75x + 2 = 12 x = (12 - 2) / 0.75 x = 13.33
If: 3x+6 = 12 Then: x = 2
If you mean: y = -8 and y = -2x-12 then the solution is x = -2 and y = -8
molarity = moles/litre [solution] = 12 mol/6 L [solution] = 2 mol/L = 2 M
The pH of a solution can be calculated using the formula: pH = -log[OH-]. Therefore, for a solution with [OH-] concentration of 10-12 M, the pH would be 12.
The solution to 0.5 percent of what number is 12 is 2,400. The number name is 2 thousand 400.
It simplifies to: -4x-12
No