31
First of all, 31 is 3. Now 3-2 is 1/32, which is 1/9. So the answer is 3/9, or 1/3. If by positive indices you mean positive exponents, that would be 1/31, because 1 plus -2 is -1, so you get 3-1 which is 1/31.
(1/2) / (31/5) = (1/2) * (31/5) = 31/10 = 3.1
1 x 31, 2 x 31/2 , 3 x 31/3 etc. 31 is a prime number.
9.11 x 10-31 = 0.000000000000000000000000000000911
2 to the second power times 31
775 is NOT a prime number.775 = 5^2*31.
Dennis Miller Live - 1994 Power 2-31 was released on: USA: 18 August 1995
Mighty Morphin Power Rangers - 1993 When Is a Ranger Not a Ranger 2-31 was released on: USA: 15 November 1994
31/2*91/3 = 3.602810866
x6 + 9= x6 - (-9) since i2 = -1= (x3)2 - 9i2 factor the difference of two squares= (x3 + 3i)(x3 - 3i) since 3 = (31/3)3 and -i = i3 we can write:= [x3 - (31/3)3i3] [x3 + (31/3)3i3]= [x3 - (31/3i)3] [x3 + (31/3i)3] factor the sum and the difference of two cubes= [(x - 31/3i)(x2 + 31/3ix + (31/3)2i2)] [(x + 31/3i)(x2 - 31/3ix + (31/3)2i2)]= [(x - 31/3i)(x2 + 31/3ix - (31/3)2)][(x + 31/3i)(x2 - 31/3ix - (31/3)2)]Thus, we have two factors (x - 31/3i) and (x + 31/3i),so let's find four othersAdd and subtract x2/4 to both trinomials[x2 - x2/4 + (x/2)2 + 31/3ix - (31/3)2] [x2 - x2/4 + (x/2)2 - 31/3ix - (32/3)2] combine and factor -1= {3x2/4 - [((x/2)i))2 - 31/3ix + (31/3)2]}{3x2/4 - [((x/2)i))2 + 31/3ix + (32/3)2]} write the difference of the two squares= {((3)1/2x/2))2 - [(x/2)i - 31/3]2}{((3)1/2x/2))2 - [(x/2)i + 32/3]2]} factor the difference of two squares= {[(31/2/2)x - ((1/2)i)x - 31/3)] [((31/2/2)x + ((1/2)i)x - 31/3)]} {[((31/2/2)x) - (((1/2)i)x + 31/3)] [((31/2/2)x) + ((1/2)i)x + 31/3)]}= {[(31/2/2)x - ((1/2)i)x + 31/3)] [((31/2/2)x + ((1/2)i)x - 31/3)]} {[((31/2/2)x) - ((1/2)i)x - 31/3)] [((31/2/2)x) + ((1/2)i)x + 31/3)]} simplify= {[((31/2 - i)/2))x + 31/3)] [((31/2 + i)/2))x - 31/3)]} {[((31/2 - i)/2))x - 31/3)] [((31/2+ i)/2))x + 31/3)]}so we have the 6 linear factors of x2 + 9.1) (x - 31/3i)2) (x + 31/3i)3) [((31/2 - i)/2))x + 31/3)]4) [((31/2 + i)/2))x - 31/3)]5) [((31/2 - i)/2))x - 31/3)]6) [((31/2+ i)/2))x + 31/3)]Check: Multiply:[(1)(2)][(3)(5)][(4)(6)]A) (x - 31/3i)(x + 31/3i) = x +(31/3)2B) [((31/2 - i)/2))x + 31/3)] [((31/2 - i)/2))x - 31/3)] = [(1 - (31/2)i)/2]x2 - (31/3)2C) [((31/2 + i)/2))x - 31/3)][((31/2+ i)/2))x + 31/3)] = [(1 + (31/2)i)/2]x2 - (31/3)2Multiply B) and C) and you'll get x4 - (31/3)2x2 + (31/3)4Now you have:[x +(31/3)2][x4 - (31/3)2x2 + (31/3)4] = x6 + 9
31/2 = 100*31/2 % = 350%31/2 = 100*31/2 % = 350%31/2 = 100*31/2 % = 350%31/2 = 100*31/2 % = 350%
311 = 31
2 raised to the power of 100 is a very large number. It is equal to 1,267,650,600,228,229,401,496,703,205,376. This is because when you raise 2 to the power of 100, you are essentially multiplying 2 by itself 100 times. This results in a number with 31 digits.
31
9.1110^-31 = 0.0000000000000000000000000000017924727177237390824301377373890253017876541885683
31^9 is equal to 26,439,622,160,671.