(6 x 5) / 2 = 3 x 5 so (30/2)=(3 x 5) 15=15
3 x 2- 5 = 1 3x 2 =6 6 - 5 = 1 so one is the answer
It is about 2.236You want a number X such that X^6=125.125= 5*5*5= 5^3.So, X^6=5^3.3=6*(1/2)= 6/2.So, X^6= 5^(6/2).Take the sixth root on both sides of the equation. This gives:X= 5^(1/2)= Sqr Rt (5) is the number.
15 x 2 3 x 10 10 x 3 2 x 15 6 x 5 5 x 6
5/6 x 12/5 = 2
thirty 30 = 2 x 15 = 3 x 10 = 5 x 6 = 6 x 5 furthermore, of 2 3 5 6 the 2 and 3 are not needed, as 6 is already 2 x 3 so only 5 and 6 are in question.
1/2 x + 6 = 11 1/2 x + 6 - 6 = 11 - 6 1/2 x = 5 2*(1/2 x) = 5*2 x = 10 1/2 of 10 is 5, 5 plus 6 is 11 QED
2x - 6 = 4 2x = 4 + 6 = 10 x = 10/2 = 5 ∴ x = 5
2x2 - 5x + 6 = ?x = -1(2 x (-1)2) - (5 x -1) + 6 = ?(2 x 1) - (-5) + 6 = ?2 + 5 + 6 = 13
- 5 - x + 2 - x + 6 - x + 10 - x = -5 + 2 + 6 + 10 - x - x - x - x = 13 - 4x
That is calculated as (6 x 5 x 4) / (1 x 2 / 3).That is calculated as (6 x 5 x 4) / (1 x 2 / 3).That is calculated as (6 x 5 x 4) / (1 x 2 / 3).That is calculated as (6 x 5 x 4) / (1 x 2 / 3).
12-5(6-3x)2(6-x)-8x = -30x^2 + 232x -348
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
656,562 =(6 x 100000) + (5 x 10000) + (6 x 1000) + (5 x 100) + (6 x 10) + (2 x 1) or(6 x 105) + (5 x 104) + (6 x 103) + (5 x 102) + (6 x 101) + (2 x 100)
656,562 =(6 x 105) + (5 x 104) + (6 x 103) + (5 x 102) + (6 x 101) + (2 x 100) OR(6 x 100,000) + (5 x 10,000) + (6 x 1,000) + (5 x 100) + (6 x 10) + (2 x 1)
(6 x 5) / 2 = 3 x 5 so (30/2)=(3 x 5) 15=15
107 (to the base 10) = (2 x 36) + (5 x 6) + (5 x 1) = (2 x 62) + (5 x 61) + (5 x 60) = 255 ( to the base 6).