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Write three ways to find 3 x 2 x 4?

3 x 2 x 4 = 24 (3 x 2) x 4 = 6 x 4 = 24 3 x (2 x 4) = 3 x 8 = 24 2 x (3 x 4) = 2 x 12 = 24


What are the factors to multiply 144 using more than 2 factors?

2 x 2 x 2 x 2 x 3 x 3 2 x 2 x 2 x 2 x 9 2 x 2 x 3 x 3 x 4 2 x 2 x 36 2 x 4 x 18 2 x 2 x 2 x 3 x 6 2 x 2 x 4 x 9 2 x 8 x 9 2 x 2 x 3 x 12 4 x 4 x 9 4 x 6 x 6 3 x 3 x 16 3 x 4 x 12 2 x 6 x 12 3 x 3 x 4 x 4 2 x 3 x 24


What is two thirds of two thirds of a cup?

2/3 x 2/3 = 4/9.2/3 x 2/3 = 4/9.2/3 x 2/3 = 4/9.2/3 x 2/3 = 4/9.


How do you factor x squared plus x minus one half?

(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2


How to make the numbers 2 4 5 6 7 8 9 10 11 12 13 14 15 Only using the numbers 1 2 3 4 once in order of operation please help mee?

1 = (1 + 4) ÷ (2 + 3) 2 = 4 - 3 + 2 - 1 3 = (4 + 3 - 1) ÷ 2 4 = (4 + 3 + 1) ÷ 2 5 = (4 x 2 - 3) x 1 6 = 4 + 3 - 2 + 1 7 = (4 + 3) x (2 - 1) 8 = 4 + 3 + 2 - 1 9 = 4 + 3 + 2 x 1 10 = 4 + 3 + 2 + 1 11 = 4 x 2 + 3 x 1 12 = 4 x 3 x (2 - 1) 13 = 3 x 4 + 2 - 1 14 = 3 x 4 + 2 x 1 15 = 3 x 4 + 2 + 1


What is the LCM of 2 3 4?

12. (6 x 2, 4 x 3 and 3 x 4)


What is a factor string of 36?

36/2=18 18/2=9 9/3=3 36/3=12 12/2=6 6/2=3 36/4=9 9/3=3 36/6=6 6/2=3


What is the answer to (2)(3)(4)?

2 x 3 x 4 = 24


What is 2 and 3 4ths x 3?

(2 3/4) x 3 = 11/4 x 3 = 33/4 = 8 1/4


What is the prime factorization of 4 and 243?

2 x 2 =4 3 x 3 x 3 x 3 x 3 = 243


Divide x2 - x - 12 by x - 4?

(x^2 - x - 12) = (x^2 - 4x + 3x -12) = x(x -4) + 3(x -4) = (x-3) x (x-4) Hence (x^2 - x - 12) divided by (x -4) is (x-3)


How do you solve 3 ln x - ln 2 equals 4?

3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)