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What are the first ten multiples of 77?
The first ten positive integer multiples of 77 are: 1 x 77 = 77 2 x 77 = 154 3 x 77 = 231 4 x 77 = 308 5 x 77 = 385 6 x 77 = 462 7 x 77 = 539 8 x 77 = 616 9 x 77 = 693 10 x 77 = 770
What is the LCM of 140 and 77?
LCM x GCD = 140 x 77 140 = 2 x 2 x 5 x 7 77 = 7 x 11 GCD = 7 LCM = 140 x 77 / 7 = 140 x 11 = 1540
What is 77 2?
There is a missing operator:If it is a plus: 77 + 2 = 79If it is a minus: 77 - 2 = 75If it is a times: 77 x 2 = 154If it is a divide: 77 / 2 = 381/2 = 38.5
Why are 77 154 231 308 and 385 the first 5 multiples of 77?
Multiples are found by multiplying a number by successive counting numbers. 77 x 1 = 77 77 x 2 = 154 77 x 3 = 231 77 x 4 = 308 77 x 5 = 385
What 2 numbers multiply to get 77?
154
How do you write 22 over 77 in simplest form?
22/77 in simplest form is 2/7, because 22/77 = 2 x 11 / 7 x 11 = 2/7
What is the LCD of 2 and 44 and 77?
2 x 2 x 7 x 11 ie 308
What prime factor is 20 multiplied be 77?
1, 7, 11, 77 Depending on what exactly you need you may or may not need to include 1 and/or 77; and 1 and 77 as well as 7 and 11 may or may not need to be grouped (paired).
What is the prime factorization of 56 101 84 77 and 213?
Prime factorization of: 56 = 2 x 2 x 2 x 7 101= 101 84 = 2 x 2 x 3 x 7 77 = 7 x 11 213 = 3 x 71
What is 38.5 divided by 0.5 work out the problem?
77
Find three consecutive integers such that the sum of their squares of 77?
let first number be x. then other two are x+1 and x+2 respectively. now x^2 +(x+2)^2 +(x+1)^2 = 77 3x^2+6x+5=77 3x^2+6x-72=0 x^2+2x-24=0 (x+6)(x-4)=0 hence x=-6 or 4 hence numbers are -6,-5,-4 or 4,5,6 From Dhruv
The sum of two and three times a number is 77?
If: 2+3x = 77 Then: x = 25
