2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
(a - 1)(a - 1)(a^2 + a + 1)(a ^2 + a + 1)
2 plus 2 equals 4plus1 equals 5minus 1 equals 4divided by 2 equals 2plus 8 equals 1010 minus 6 equals 4so it all equals to +_____29so its 29 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
If 6a divided by 2 equals 12 then A equals
no it equals 20, yes it equals 2 you illiterate piece of sh*t
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
(a - 1)(a - 1)(a^2 + a + 1)(a ^2 + a + 1)
Solve the following equation for A : 2A/3 = 8 + 4A
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All you can factor out is the common factor 2. 2(a^3 - 64)
Since you know the values of the two variables, a and y, plug it into the expression like this: 2a3 - 3ay = 6a - 3ay = 6(-1) -3(-1)(2) = -6 -3(-2) =-6 + 6 = 0
In rationalising quadratics 2a3 - 5a2 - 39 is an irrelevance. It is not a quadratic but a cubic and so not within the defined scope.
(2a3)(10a5)/4a1
2a3-16a2+30a Factor out 2a: 2a(a2-8a+15) (2a)(a-5)(a-3) This is the most factored form of this expression.
No.
2 plus 2 equals 4plus1 equals 5minus 1 equals 4divided by 2 equals 2plus 8 equals 1010 minus 6 equals 4so it all equals to +_____29so its 29 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
If 6a divided by 2 equals 12 then A equals