9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
0
(2,4) and (-4,8) y=mx+b 4=m(2)+b 4=2m+b b=y2-y1 /x2-x1 b = (8-4)/(-4-2) b=4/-2 b=-2 4=2m+-2 6=2m 3=m So your y=mx+b equation would be: y=3x+-2
6
it could men m times m, which would be 2m or m2. It would usually be 2m. ↑ that would only work for m² not 2m. 2m in that sense is 2*m not m*m. now m2 is usually associated with slope 2. m1=slope1 m2=slope2, but the numbers are usually subscripts.
1/m + 1/2m = 6 LCD is 2m (2 + 1) / 2m = 6 3/2m = 6 3/6 = 2m = 1/2 m = 1/4
m=-0.2
0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18
2m + 2 = 3m + 4 => 2m-3m = 4-2 => -m = 2 => m= -2
2m/3
Gather like terms: 2m - m + 3 + 4 = m + 7.
4m - 8 = 6m =>4m - 6m = 8 => -2m = 8 => m = -(8/2) => m = -4
You need to resubmit this so it is an equation. Could you mean 2m=m-87? If so, then follow this. subtract an m from each side: 2m-m = m-87-m simplify: m = -87 Now plug that number back in to check: 2(-87) = (-87) minus 87 -174 = -174 so it checks.
m = 9 This is because, if: m squared - 2m - 65 = 2 Then: m squared - 2m = 65 + -2 m squared - 2m = 63 So: 63 = m squared - 2m m squared - 2m = m x m - 2m This means: 63 = m (m - 2) So something times itself minus two is 63. Going through different numbers, it is clear that 9 and 7 work. So: m x (m - 2) = 9 x (9-2) = 9 x (7) = 9 x 7 = 63 M is therefore 9.
9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
It is quite easy to prove this using algebra. Suppose x is the smaller of the two odd integer. The fact that x is odd means that it is of the form 2m + 1 where m is an integer. [m integer => 2m is an even integer => 2m + 1 is odd] The next odd integer will be x + 2, which is (2m + 1) + 2 = 2m + 3 The sum of these two consecutive odd integers is, therefore, 2m + 1 + 2m + 3 = 4m + 4 = 4(m + 1) Since m is an integer, m+1 is an integer and so 4(m + 1) represents a factorisation of the answer which implies that 4 is a factor of the sum. In other words, the sum is a multiple of 4.
-1.0499999999999998