0.5 x 142 = 71
X 3 plus x-142 plus x is an equation equal to x3+2x-142.
To find two numbers that multiply to 142, we need to factorize 142 into its prime factors: 2 x 71. Therefore, the two numbers that multiply to 142 are 2 and 71.
328 * 3x / 326 = 9 So 328+x-26 = 9 = 32 So 32+x = 32 2+x = 2 so that x = 0
1000 ÷ 7 = 142 remainder 6 So, there are 142 numbers between 1 and 1000 that are evenly divisible by 7. 1 x 7 = 7 2 x 7 = 14 3 x 7 = 21 ... 142 x 7 = 994
328
2 x 2 x 2 x 41 = 328
2 x 2 x 2 x 41 = 328
2 x 2 x 2 x 41 = 328
1 x 142, 2 x 71 = 142
1 x 142, 2 x 71, 71 x 2, 142 x 1
2 x 2 x 2 x 41 = 328
328 = 2 x 2 x 2 x 41 or 23 x 41
328 = 23 x 41
897 x 328 = 294,216
328 x 345 = 113,160
328 = 2 x 2 x 2 x 41 OR 23 x 41