Let their ages be x and y: x+y = 51 => y = 51-x xy = 648 x(51-x) = 648 51x-x2-648 = 0 x2-51x+648 = 0 (x-24)(x-27) = 0 x = 24 or x = 27 So their ages were 24 and 27 Check: 24+27 = 51 and 24*27 = 648
1 x 346, 2 x 173.
72 x 9 = 648
40(x) + 7(2x)=648 40x + 14x = 648 54x = 648 x = 12 ■
1.2346
648 = ?%*900 648 = x/100*900 648 = 9x x = 648/9 x = 72
46 x 346 = 15916
346 x 2,656= 918,976
The two numbers that form a product of 648 are 27 and 24. This is because 27 x 24 = 648. These numbers are factors of 648, as they evenly divide into 648 without leaving a remainder.
The prime factorization of 648 is: 2 x 2 x 2 x 3 x 3 x 3 x 3It is: 2*2*2*3*3*3*3 = 648
Let their ages be x and y: x+y = 51 => y = 51-x xy = 648 x(51-x) = 648 51x-x2-648 = 0 x2-51x+648 = 0 (x-24)(x-27) = 0 x = 24 or x = 27 So their ages were 24 and 27 Check: 24+27 = 51 and 24*27 = 648
1 x 346, 2 x 173.
346 = (3 x 100) + (4 x 10) + (6 x 1)
346 = (3 x 100) + (4 x 10) + (6 x 1)
346 x 45 = 15570
648 = 23 x 34
To express 648 as a product of its prime factors, we first need to find its prime factors. We start by dividing 648 by the smallest prime number, which is 2. 648 รท 2 = 324. Then, we divide 324 by 2 again: 324 รท 2 = 162. Continuing this process, we find that the prime factors of 648 are 2 x 2 x 2 x 3 x 3 x 3 x 3, or 2^3 x 3^4.