5 tens x 7 tens = 35 hundreds = 3 thousands 5 hundreds.
Yes.
Two of them.
The number that has 3 hundreds, 20 tens, and 16 ones can be written as 320 + 16 = 336. In this number, there are 3 hundreds (300), 20 tens (20 x 10 = 200), and 16 ones. When you add these together, you get the final number, 336.
To solve this, we first need to convert the hundreds into tens. 2 hundreds is equal to 200, so that is 20 tens. Then, we add the 14 tens to get a total of 34 tens. Finally, we add the 3 ones to get a final total of 342.
5 tens x 7 tens = 35 hundreds = 3 thousands 5 hundreds.
Yes.
Two of them.
10*20 = 200
20 tens = 200 200 ones = 200 56 hundreds = 5,600 Total = 6,000 or six thousand.
4 hundreds means 4x100=400. Two tens mean 2x10=20 Thus, their sum would be 400+20=420.
YES (20 x 10 = 200)
The number that has 3 hundreds, 20 tens, and 16 ones can be written as 320 + 16 = 336. In this number, there are 3 hundreds (300), 20 tens (20 x 10 = 200), and 16 ones. When you add these together, you get the final number, 336.
To solve this, we first need to convert the hundreds into tens. 2 hundreds is equal to 200, so that is 20 tens. Then, we add the 14 tens to get a total of 34 tens. Finally, we add the 3 ones to get a final total of 342.
One Ten = Ten Ones. 200 = 2 Hundreds, 20 Tens or 200 Ones.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
In 12000, there are;12 thousands120 hundreds and1200 tens