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∙ 10y ago
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What times 4 equals 140?
35X4=120
How many solar watts are required to charge a battery of 35Ah?
It depends on hourexample: for 4 hour back up35AH means 35 amps/1 hrfor 4 hrs : 35x4 = 140 ampsSolar watt required - 140 x 12 (Vx I) = 1680 wattsPlease let me know this calculation is correct or notrshashiku@gmail.com
What is 8 and one seventh minus 4 and 4 fifth?
8 1/7 - 4 4/5= ?change 8 1/7 into improper fraction, which is 57/7and change 4 4/5 into improper fraction, which is 24/5now what is the lowest common multiple, 35so 57x5=285/7x5=35, 285/35and 24x5=120/5x7=35, 120/35285/35 - 120/35= 165/ 35now change 165/35 into a mixed number, so 35x4= 140 with 25 left over, so the answer is 4 25/35.
2x-3 parenthesis 2x plus 3 parenthesis equals?
(2x-3)(2x+3) can be multiplied out using the FOIL method, which stands for:FirstOuterInnerLastThis method only works for the multiplication of two binomials, so don't rely exclusively upon it.For the "first" part, multiply the two first terms of the binomials together:(2x)(2x)=4x2For the "outer" part, multiply the two outermost terms together:(2x)(3)=6xFor the "inner" part, mulitply the two innermost terms together:(2x)(-3)=-6xFor the "last" part, mulitply the two last terms of each binomial together:(3)(-3)=-9Add all of these sub-calculations together to get your final result:4x2+6x-6x-9As you can see, 6x-6x=0, so these two terms will cancel out, leaving:4x2-9Another way of doing this multiplication is to see it as an application of the distributive property, but instead of a single number distributed across a binomial, it is another binomial. This is what the FOIL method essentially does, but it creates a handy mnemonic to remember it. To see it as a distributive problem, visualize it like this as I distribute (2x-3) across (2x+3):(2x-3)(2x+3)=(2x-3)(2x)+(2x-3)(3)=(4x2-6x)+(6x-9)=4x2-9As you can see, the same answer is reached. This method of distributing one entire term across the other polynomial holds true for more complicated multiplications, so it is the most accurate way to memorize how to handle these problems. A simplification of something like this:(x-7)(5x4+4x3-x2+9x-2)cannot be handled with such a convenient crutch as the FOIL method, but realizing it is simply distribution makes it very doable:(x-7)(5x4)+(x-7)(4x3)-(x-7)(x2)+(x-7)(9x)-(x-7)(2)(5x5-35x4)+(4x4-28x3)-(x3-7x2)+(9x2-63x)-(2x-14)5x5-35x4+4x4-28x3-x3+7x2+9x2-63x-2x+145x5-31x4-29x3+16x2-65x+14And in case that side-track example distracted you from the real answer, it was 4x2-9
