333
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|x-9| = 37-x Suppose x-9 < 0 then 9-x = 37-x which is inconsistent. So 9-x > 0. Then x-9 = 37-x Add x to both sides: 2x-9 = 37 Add 9 to both sides: 2x = 46 so that x = 23.
0.925
-42 + 37 - (6 x 9) + (7/4) = -57.25
1 x 999, 3 x 333, 9 x 111, 27 x 37
First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.