|x-9| = 37-x Suppose x-9 < 0 then 9-x = 37-x which is inconsistent. So 9-x > 0. Then x-9 = 37-x Add x to both sides: 2x-9 = 37 Add 9 to both sides: 2x = 46 so that x = 23.
-42 + 37 - (6 x 9) + (7/4) = -57.25
1 x 999, 3 x 333, 9 x 111, 27 x 37
First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.First convert it to an improper fraction: 4 1/9 = 37/9.Then just exchange the numerator and the denominator: 1 / (37/9) = 9/37.
double previous number then alternately either add 1 or deduct 1 9 x 2 = 18 then + 1 = 19 19 x 2 = 38 then - 1 = 37 37 x 2 = 74 then + 1 = 75 75 x 2 = 150 then - 1 = 149 149 x 2 = 298 then + 1 = 299 299 x 2 = 598 then - 1 = 597
|x-9| = 37-x Suppose x-9 < 0 then 9-x = 37-x which is inconsistent. So 9-x > 0. Then x-9 = 37-x Add x to both sides: 2x-9 = 37 Add 9 to both sides: 2x = 46 so that x = 23.
5 x 9 x 37 - 32 = 1633
x+x+9=83 2x=83-9=74 x=37 boy+37
9x = 333 Therefore, x = 333/9 x = 37
Let's see... 4x+10=x+37 x = 9
x = -7
Divide the number into 26 equal parts, and then share those parts into 7/26ths, 9/26ths, and 10/26ths. 962 / 26 = 37 37 x 7 = 258 37 x 9 = 333 37 x 10 = 370 Therefore your answer is 258 : 333 : 370.
426
x+9=xx x+9=x^2 x^2-x-9=0 Quadratic formula: x=[1±√(1+36)]/2 x=(1±√37)/2
1 x 999, 3 x 333, 9 x 111, 27 x 37.
Being a prime number, 37 is only in the 1, and 37 times tables. (1 x 37)
666