Three Hundred (space) and thirty three
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Perimeter = 33+33+3+3 = 72 m
How to solve: 2/3 + 1/11 2/3 X 11 = 22/33 1/11 X 3 = 3/33 22/33 + 3/33 = 25/33 25/33 can not be reduced so it is the final answer.
3x = 33 Therefore, x = 33/3 x = 11
1 x 33, 3 x 11 = 33
three and five thirty-thirds 3 + 5/33 3-5/33 3.5/33 104/33