Three Hundred (space) and thirty three
Perimeter = 33+33+3+3 = 72 m
How to solve: 2/3 + 1/11 2/3 X 11 = 22/33 1/11 X 3 = 3/33 22/33 + 3/33 = 25/33 25/33 can not be reduced so it is the final answer.
3x = 33 Therefore, x = 33/3 x = 11
1 x 33, 3 x 11 = 33
three and five thirty-thirds 3 + 5/33 3-5/33 3.5/33 104/33
The factors of 33 are 1, 3, 11, and 33.
33
33/99 = 33/(3*33) = 1/3
The LCM of 3, 11, and 33 is 33.
Factors of 33 are 1, 3, 11, and 33.
The factors of 33 are: 1, 3, 11, 33
33 is [3 11] 105 is [3 3 3 5] Common factors: [3] GCF=3 LCM = 33 / 3 * 105 = 1155
Factors of 33=1,33,3,11 Factors of 99=1,99,3,33,11,99 HCF of 33&99 is 33
63 = (2x3)3 = 23 x 33 36 = 33+3 = 33 x 33 As 2 ≠ 3 then 23 ≠ 33 ⇒ 63 = 23 x 33 ≠ 33 x 33 = 36 ⇒ 63 ≠ 36
3/33 = 0.090909090 . . .
11
3 divided by 33 is 0.09090