3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
4x + 3y=9 x=0 y=3
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
5y - 2 + y + 52 = 6y + 50 - 3y6y + 50 = 9y + 50y = 0
(0,-4)
3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
x = 3 and y = 0
(-1, 0)
4x + 3y=9 x=0 y=3
x=4 y=0
(6, 0) and (0, 8)
It's an hyperbola equation.
For y - 2y - 3y equals 0, y equals 0.
(4, -7)
It works out that they intersect at: (4, -7)
y intercept: x = 0 3y = 0 y = 0 x intercept: y=0 -4x = 0 x = 0 (0,0)
7x + 3y = 14 5x + 9y = 10 __________ (subtract bottom from top) 2x -6y = 4, therefore 2x = 4 + 6y, therefore x = 2 + 3y Insert x = 2 + 3y into the original equation and calculate 7(2 + 3y) +3y = 14 14 + 21y +3y = 14 24y = 0 y = 0 If y= 0, then x = 2 FINAL ANSWER!