The algebraic expression for "4 decreased by the quotient of a number and 7" can be represented as 4 - (x/7), where x is the variable representing the number. The expression first calculates the quotient of the number and 7 by dividing x by 7, and then subtracts that quotient from 4. This expression captures the mathematical operation described in the question.
x/8
x/15
N/8
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
18 - 3n
The question is ambiguous so the answer is one of:3/n - 5 or 3/(n-5)
x/8
x/15
x+2=
The algebraic expression for a number decreased by 8 can be represented as ( x - 8 ), where ( x ) is the variable representing the unknown number. This expression indicates that 8 is subtracted from the value of ( x ).
The algebraic expression for the quotient of ( c ) and 8 is written as ( \frac{c}{8} ). This expression represents the result of dividing the variable ( c ) by the number 8.
N/8
N/9
-(n/12)
The algebraic expression for 14 less than the quotient of 63 and the number H is ( \frac{63}{H} - 14 ). This expression first calculates the quotient of 63 and H, and then subtracts 14 from that result.
The algebraic expression for 84 divided by the number ( z ) is ( \frac{84}{z} ). This expression represents the quotient of 84 and the variable ( z ).
6x/23