The algebraic expression for "4 decreased by the quotient of a number and 7" can be represented as 4 - (x/7), where x is the variable representing the number. The expression first calculates the quotient of the number and 7 by dividing x by 7, and then subtracts that quotient from 4. This expression captures the mathematical operation described in the question.
x/8
x/15
N/8
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
18 - 3n
The question is ambiguous so the answer is one of:3/n - 5 or 3/(n-5)
x/8
x+2=
x/15
N/8
-(n/12)
N/9
It can be: x-7
6x/23
(x/7)2
8/m
x/4