(7*sqrt(2))/2 (Seven time the square root of 2, divided by two)
It could be written as 28 divided by radical 3. However, you will normally be required to rationalise the denominator which brings you back to 28 radical 3 divided by 3.
6
84
2
2
2 divided brly radical 15 = 0.13333333333333333
9*radical(3)/2 = 4.5*radical(3) = 7.794 approx.
(7*sqrt(2))/2 (Seven time the square root of 2, divided by two)
76
2 radical(8) = 4 radical(2)
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
250
4 radical 6
If we factor 60, we get 60 = 2 * 2 * 3 * 5 So sqrt ( 60 ) = sqrt (2 * 2 * 3 * 5) = sqrt (2 * 2) * sqrt (3 * 5) = 4 * sqrt( 15 ) ____________________________________________________________ actually if you do by just using the simpler way you should get 2 radical 15 since , 60 has the closest perfect square of 4 and non perfect of 15 this is how you should solve radical 60 = radical 4 times radical 15 radical 60 = simplify the 4 to 2 and leave radical 15 So , radical 60 = 2 radical 15 not what is above .
8√12/5√4 = 8√(3*4)/5√4 = 8(√3)/5 = 8/5*√3
4 x2