16/25 (4/5)2 = 4/5 x 4/5 = (4 x 4)/(5 x 5) = (42)/(52) = 16/25
No, multiplication is associative. 5 x (4 x 3) = 4 x (5 x 3) = 3 x (5 x 4) = 5 x 4 x 3 = 60
That's a total of... 17148496850051.5
5^4 = 5 x 5 x 5 x 5 = 625
5 x 4 x 4000 = 80000
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
(X-5)(X+4)=0 so X-5=0 -----X=5 and X=4=0 so X=-4 it factors to (X-5)(X+4) so X=5,-4
(4 x 11) + (4 x 10) = 4 x 21 = 84
[(7+3)/(x+4)] / [(x-5)/(2-4)] =[(7+3)/(x+4)] * [(2-4)/(x-5)] =[10*(x-5)] / [-2*(x+4)] =-5*[(x-5)/(x+4)]
4/5 x 5/4 = (4 x 5)/(5 x 4) = 20/20 = 1
x/-4 + 5 = -5x/-4 +5 -5 = -5 -5x/-4 = -10x/-4 x -4 = -10 x -4x = 40
5 x 4 equals 4 x 5 is commutative property.
no4 x 4 x 4 = 64 = 4³5 x 5 x 5 = 125 = 5³
16/25 (4/5)2 = 4/5 x 4/5 = (4 x 4)/(5 x 5) = (42)/(52) = 16/25
No, multiplication is associative. 5 x (4 x 3) = 4 x (5 x 3) = 3 x (5 x 4) = 5 x 4 x 3 = 60
That's a total of... 17148496850051.5
(x+4)(x+5) = 0 x = -4 v x= -5 However this can also be an answer: (x+4)(x+5) = 0 x2 + 9x + 20 = 0