It is an expression and can be simplified to: 3d+f+1
3f - 2 = 4f + 5 You are looking for an unknown number, f. In the end, you want to know that f equals a specific number; the number on one side of the equation and f on the other. So first you want to get it in that format: -2 = 5 + 4f - 3f -2 - 5 = 4f - 3f Now solve: -7 = f You can see that f equals -7. This is what you're looking for.
When you have 3f plus f plus 4f, you are adding together like terms. In this case, the variable "f" is the same, so you can add the coefficients together. 3f + f is 4f, and when you add 4f to that, you get 8f. Therefore, 3f + f + 4f equals 8f.
It can be simplified to: 4f+2e
2+2+2+2+2+2+2+2+2+2+2+2+(2x0) =2+2+2+2+2+2+2+2+2+2+2+2+0 =24
10
f = -2
3f - 2 = 4f + 5 You are looking for an unknown number, f. In the end, you want to know that f equals a specific number; the number on one side of the equation and f on the other. So first you want to get it in that format: -2 = 5 + 4f - 3f -2 - 5 = 4f - 3f Now solve: -7 = f You can see that f equals -7. This is what you're looking for.
When you have 3f plus f plus 4f, you are adding together like terms. In this case, the variable "f" is the same, so you can add the coefficients together. 3f + f is 4f, and when you add 4f to that, you get 8f. Therefore, 3f + f + 4f equals 8f.
It can be simplified to: 4f+2e
The maximum number of electrons that can exist in 4f orbitals is 14, following the principle that each orbital can hold a maximum of 2 electrons with different spins.
14
14
3 nodes in 4f
The possible values for a 4f sublevel are 14. This means there can be a maximum of 14 electrons in a 4f sublevel.
[Xe] 6s^2 4f^14 5d^4
[Xe] 4f 12 6s 2
Electrons are added to the 4f orbitals from the 5d orbitals in the lanthanide and actinide series of elements. The 4f orbitals are filled after the 5d orbitals are filled due to the overlap in energy levels, leading to the stability of the 4f electrons in these elements.