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How do you get the product of 2 times the square root of 5 and 4 times the square root of 10?

Here, with probably a lot more steps than required, is the answer: [2*sqrt(5)]*[4*sqrt(10)]=2*4*sqrt(5)*sqrt(10) = 8*sqrt(5)*sqrt(10) = 8*sqrt(5*10) = 8*sqrt(5*5*2) = 8*5*sqrt(2) = 40*sqrt(2)


How do you solve square root of 720?

Notice that 720 = (4 x 5 x 36)sqrt(720) = sqrt(4 times 5 times 36)= sqrt(4) times (sqrt(5) times sqrt(36)= (2) times sqrt(5) times (6)= 12 sqrt(5)


What is 5 times the square root of 5 divided by the square root of 2?

5*sqrt(5)/sqrt(2) = 5*sqrt(5/2) = 5*sqrt(2.5) = 7.91, approx.


What is the radical of 50 simplified to be?

The radical of 50 can be simplified by factoring it into its prime components: (50 = 25 \times 2 = 5^2 \times 2). Therefore, the square root of 50 can be expressed as (\sqrt{50} = \sqrt{25 \times 2} = \sqrt{25} \times \sqrt{2} = 5\sqrt{2}). Thus, the simplified form of the radical of 50 is (5\sqrt{2}).


What is the square root of 2 times the square root of 75?

sqrt(2)*sqrt(75) = sqrt(2)*sqrt(3*25) = sqrt(2)*sqrt(3)*sqrt(25) = sqrt(2*3)*5 = 5*sqrt(6) = 12.247 approx.


What is the simplified expression for 6 radical 500?

To simplify ( 6 \sqrt{500} ), first break down ( 500 ) into its prime factors: ( 500 = 100 \times 5 = 10^2 \times 5 ). Therefore, ( \sqrt{500} = \sqrt{100 \times 5} = \sqrt{100} \times \sqrt{5} = 10\sqrt{5} ). Now, substituting back, we have ( 6 \sqrt{500} = 6 \times 10 \sqrt{5} = 60 \sqrt{5} ). Thus, the simplified expression is ( 60 \sqrt{5} ).


What is root 2 times root 2?

The product of (\sqrt{2}) and (\sqrt{2}) is calculated as follows: (\sqrt{2} \times \sqrt{2} = \sqrt{2 \times 2} = \sqrt{4} = 2). Therefore, (\sqrt{2} \times \sqrt{2} = 2).


What is the square root of 5 times the square root of 2 plus the square root of 8?

=SQRT(5)*SQRT(2)+SQRT(8) is 5.99070478491457


Simplify 3square root 175?

To simplify (3\sqrt{175}), first factor (175) into prime factors: (175 = 25 \times 7 = 5^2 \times 7). This allows us to simplify the square root: (\sqrt{175} = \sqrt{25 \times 7} = \sqrt{25} \times \sqrt{7} = 5\sqrt{7}). Therefore, (3\sqrt{175} = 3 \times 5\sqrt{7} = 15\sqrt{7}).


2-square root of -5 squared?

7


How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?

x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)


What is radical 32 simplified?

Radical 32 can be simplified by factoring it into its prime factors. Since 32 is equal to (2^5), we can express (\sqrt{32}) as (\sqrt{16 \times 2}), which simplifies to (\sqrt{16} \times \sqrt{2} = 4\sqrt{2}). Thus, the simplified form of radical 32 is (4\sqrt{2}).