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2-square root of -5 squared?
7
What is the multiplicative inverse of 5 plus 3 square root of 2?
1/[5 + 3*sqrt(2)] = [5 - 3*sqrt(2)]/{[5 + 3*sqrt(2)][5 - 3*sqrt(2)]} = [5 + 3*sqrt(2)]/[25 - 18] = [5 - 3*sqrt(2)]/7
What is the exact value of the expression 11 square root 8 plus 6 square root 12 minus 5 square root 2 Show your work?
11*sqrt(8) + 6*sqrt(12) - 5*sqrt(2) = 11*sqrt(4*2) + 6*sqrt(4*3) - 5*sqrt(2) = 11*sqrt(4)*sqrt(2) + 6*sqrt(4)*sqrt(3) - 5*sqrt(2) = 11*2*sqrt(2) + 6*2*sqrt(3) - 5*sqrt(2) = 22*sqrt(2) - 5*sqrt(2) + 12*sqrt(3) = 17*sqrt(2) + 12*sqrt(3) and that cannot be simplified further.
What is the square root of 12 times 2 square root 18 Times Square root 24?
sqrt(12)*2*sqrt(18)*sqrt(24) = sqrt(4*3)*2*sqrt(2*9)*sqrt(4*2*3) = sqrt(4)*sqrt(3)*2*sqrt(2)*sqrt(9)*sqrt(4)*sqrt(2)*sqrt(3) = 2*sqrt(3)*2*sqrt(2)*3*2*sqrt(2)*sqrt(3) = 24*sqrt(2)*sqrt(2)*sqrt(3)*sqrt(3) = 24*2*3 = 144
What is the square root of 10x Times Square root of 8x equals?
sqrt(10x)*sqrt(8x) = sqrt(80x2) = sqrt(16x2*5) = sqrt(16x2)*sqrt(5) = 4x*sqrt(5)
How do you get the product of 2 times the square root of 5 and 4 times the square root of 10?
Here, with probably a lot more steps than required, is the answer: [2*sqrt(5)]*[4*sqrt(10)]=2*4*sqrt(5)*sqrt(10) = 8*sqrt(5)*sqrt(10) = 8*sqrt(5*10) = 8*sqrt(5*5*2) = 8*5*sqrt(2) = 40*sqrt(2)
How do you solve square root of 720?
Notice that 720 = (4 x 5 x 36)sqrt(720) = sqrt(4 times 5 times 36)= sqrt(4) times (sqrt(5) times sqrt(36)= (2) times sqrt(5) times (6)= 12 sqrt(5)
What is 5 times the square root of 5 divided by the square root of 2?
5*sqrt(5)/sqrt(2) = 5*sqrt(5/2) = 5*sqrt(2.5) = 7.91, approx.
What is the square root of 2 times the square root of 75?
sqrt(2)*sqrt(75) = sqrt(2)*sqrt(3*25) = sqrt(2)*sqrt(3)*sqrt(25) = sqrt(2*3)*5 = 5*sqrt(6) = 12.247 approx.
What is the square root of 5 times the square root of 2 plus the square root of 8?
=SQRT(5)*SQRT(2)+SQRT(8) is 5.99070478491457
What is the formula volume of regular objects?
LxWxH=Answer _ cm3
2-square root of -5 squared?
7
How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?
x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
How do you factor this x4-x2-1?
Let say X=x2 Then x4-x2-1=X2-X-1 Delta (for X) = (-1)2 - 4 x 1 x -1 = 5 X2-X-1 = [X - (1 - sqrt(5))/2] [X - (1 + sqrt(5))/2] and as x2=X x4-x2-1 = [x2 - (1 - sqrt(5))/2] [x2 - (1 + sqrt(5))/2] as a2+b2=(a+ib)(a-ib) and a2-b2=(a-b)(a+b) x4-x2-1 = [x - sqrt((1 + sqrt(5))/2)] [x + sqrt((1 + sqrt(5))/2)] [x - i sqrt((1 - sqrt(5))/2)] [x + i sqrt((1 - sqrt(5))/2)] sqrt((1+sqrt(5))/2) = 1/2 sqrt(2+2 sqrt(5)) sqrt((1-sqrt(5))/2) = 1/2 i sqrt(-2+2 sqrt(5))
How do you find the vector of magnitude 2 in the direction of vector i plus 2j?
The magnitude of (i + 2j) is sqrt(5). The magnitude of your new vector is 2. If both vectors are in the same direction, then each component of one vector is in the same ratio to the corresponding component of the other one. The components of the known vector are 1 and 2, and its magnitude is sqrt(5). The magnitude of the new one is 2/sqrt(5) times the magnitude of the old one. So its x-component is 2/sqrt(5) times i, and its y-component is 2/sqrt(5) times 2j. The new vector is [ (2/sqrt(5))i + (4/sqrt(5))j ]. Since the components of both vectors are proportional, they're in the same direction.
How to simplify square root of 50 - the square root of 18?
32
What is two radical six minus 5 radical 24?
2 sqrt(6) - 5 sqrt(24) = 2 sqrt(6) - 5 sqrt(4 x 6) = 2 sqrt(6) - 5 sqrt(4) sqrt(6) =2 sqrt(6) - 5 x 2 sqrt(6) = 2 sqrt(6) - 10 sqrt(6) =-8 sqrt(6)
