Oh, dude, math time! So, 70 times 365 is 25,550. That's like, how many times I've thought about ordering takeout this year. But hey, who's counting, right?
Yes because 25x2-70x+49 = (5x-7)(5x-7) when factored
49x²+70x+25 = (7x+5)² since the root (-70/(2*49)) of the quadratic equations is -5/7 (discriminant = 70²-4*49*25 = 0)
365 + 365 + 365 + 308 = 1,403
42% of 365= 42% * 365= 0.42 * 365= 153.3
1,095.
252-70x+49 = (5x-7)(5x-7) when factored
Yes because 25x2-70x+49 = (5x-7)(5x-7) when factored
Yes.
To solve the equation (2x - 72x - 5 = 0), first combine like terms: (2x - 72x) simplifies to (-70x), giving you (-70x - 5 = 0). Next, add 5 to both sides: (-70x = 5). Finally, divide both sides by (-70) to find (x = -\frac{1}{14}).
1970
7(x-5)^2
49x²+70x+25 = (7x+5)² since the root (-70/(2*49)) of the quadratic equations is -5/7 (discriminant = 70²-4*49*25 = 0)
Well, darling, the antiderivative of 70x is 35x^2 + C, where C is the constant of integration. It's as simple as that, honey. Just integrate like there's no tomorrow and don't forget that little "+ C" at the end.
To foil the equation (7x + 10)(-10x - 1), multiply each term in the first binomial by each term in the second binomial. This results in: (7x \cdot -10x = -70x^2) (7x \cdot -1 = -7x) (10 \cdot -10x = -100x) (10 \cdot -1 = -10) Now, combine the like terms: (-70x^2 - 7x - 100x - 10 = -70x^2 - 107x - 10). So, the final result is (-70x^2 - 107x - 10).
5(4x - 3)(2x + 5)
It will run well on 215/70x 15.
10X^2