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What else can I help you with?
What are the first 7 multiples of 6?
7, 14, 21, 28, 35, 421x7=72x7=14and soooo onThe first 6 multiples of 7 are 7, 14, 21, 28, 35, 42.
What is the meaning of product rule?
The product rule is a formula that is used to find the derivative of the product of two or more functions. It is summarized as thus: y' = u x v' + v x u' ("first times the derivative of the second, plus the second times the derivative of the first"). Ex: y = (2x4 + 6x3 + 9x) X (3x2 + x7+ 12) y' = (2x4 + 6x3 + 9x) X (6x + 7x6) + (3x2 + x7+ 12) X (8x3 + 18x2 + 9) y' = 12x5 + 14x10 + 36x4 + 54x2 + 63x7 + 24x5 + 54x4 + 27x2 + 8x10 + 18x9 + 9x7 + 96x3 + 216x2 + 108 y' = 36x5 + 22x10 + 90x4 + 297x2 + 72x7 + 18x9 + 96x3 + 108
If you have 100.00 to buy 100 animals cows are 1.00goats are 50 and chickens are 25 You must buy at least one of each and and total 100 animals and 100 dollars how?
Mathematically, this question has 3 variables but there are only 2 equations to solve from. Thus the need for third equation has to be eliminated by reasoning. Let: x: Number of hens y: Number of sheep z: Number of cows Thus 2 eqns. are: x+y+z=100 ---(1) x/8 + y +10z=100 ----(2) Subtract (2) from (1) to get: (7/8)x=9z =>7x=72z ---(3) It seems to get stuck here. if 7x and 72z are both made equal to the LCM (least common multiple) of 7 & 72 then equation is satisfied. These being coprime the LCM =72x7. Thus, minimum values of x & z satisfying (3) are x=72 & z=7, which gives y=21 and also makes (1) true. Other values of x & z satisfying (3) would violate (1). Thus, number of hens=72, number of sheep=21 & number of cows=7. Mathematically, this question has 3 variables but there are only 2 equations to solve from. Thus the need for third equation has to be eliminated by reasoning. Let: x: Number of hens y: Number of sheep z: Number of cows Thus 2 eqns. are: x+y+z=100 ---(1) x/8 + y +10z=100 ----(2) Subtract (2) from (1) to get: (7/8)x=9z =>7x=72z ---(3) It seems to get stuck here. if 7x and 72z are both made equal to the LCM (least common multiple) of 7 & 72 then equation is satisfied. These being coprime the LCM =72x7. Thus, minimum values of x & z satisfying (3) are x=72 & z=7, which gives y=21 and also makes (1) true. Other values of x & z satisfying (3) would violate (1). Thus, number of hens=72, number of sheep=21 & number of cows=7.
Whair can you find an huge multiplycation chart?
Here up until 12's :) Look :0x1=01x1=12x1=23x1=34x1=45x1=56x1=67x1=78x1=89x1=910x1=1011x1=1112x1=12TWO'S0x2=01x2=22x2=43x2=64x2=85x2=106x2=127x2=148x2=169x2=1810x2=2011x2=2212x2=24THREE'S0x3=01x3=32x3=63x3=94x3=125x3=156x3=187x3=218x3=249x3=2710x3=3011x3=3312x3=36FOUR'S0x4=01x4=42x4=83x4=124x4=165x4=206x4=247x4=288x4=329x4=3610x4=4011x4=4412x4=48FIVES0x5=01x5=52x5=103x5=154x5=205x5=256x5=307x5=358x5=409x5=4510x5=5011x5=5512x5=60SIX'S1x6=62x6=123x6=184x6=245x6=306x6=367x6=428x6=489x6=5410x6=6011x6=6612x6=72SEVEN'S1x7=72x7=143x7=214x7=285x7=356x7=427x7=498x7=569x7=6310x7=7011x7=7712x7=84EIGHT'S1x8=82x8=163x8=244x8=325x8=406x8=487x8=568x8=649x8=7210x8=8011x8=8812x8=96NINE'S0x9=01x9=92x9=183x9=274x9=365x9=456x9=547x9=638x9=729x9=8110x9=9011x9=9912x9=108TEN'S1x10=102x10=203x10=304x10=405x10=506x10=607x10=708x10=809x10=9010x10=10011x10=11012x10=120ELEVEN'S1x11=112x11=223x11=334x11=445x11=556x11=667x11=778x11=889x11=9910x11=11011x11=12112x11=132TWELVE'S1x12=122x12=243x12=364x12=485x12=606x12=727x12=848x12=969x12=10810x12=12011x12=13212x12=144
