2/7 * 14 = 2/7 * (7*2) = 2/7 * 7 * 2 cancelling out the 7s = 2 * 2 = 4
31/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/231/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/231/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/231/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/2
There are two ways to answer this, both with the same result. 1st) two sevenths is 2/7 and any time you want to find out how much of something is in another you divide. So 2/(2/7), which is 7. 2nd) Convert 2 into a base of 7 by multipling 2*(7/7)=14/7. Then simply added 2/7 until you get 14/7. So... 2/7+2/7+2/7+2/7+2/7+2/7+2/7=14/7. Now count the number of 2/7 you wrote, and there are 7 of them. So either approach, you get 7 two sevenths are in 2.
the awnser will be 7 3+3=6+3=9 9-2=7-0=ANS=7
-7 * 2 or -2 * 7
2/7 * 14 = 2/7 * (7*2) = 2/7 * 7 * 2 cancelling out the 7s = 2 * 2 = 4
31/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/231/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/231/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/231/2 / 21/3 = (7/2) / (7/3) = (7/2)*(3/7) = 3/2 or 11/2
Let's see in a prime factorization tree. 2, 98 2, 2, 49 2, 2, 7, 7. The answer is:2 to the power of 2 and 7 to the power of 2 ;/or 2 x 2 x 7 x 7
There are two ways to answer this, both with the same result. 1st) two sevenths is 2/7 and any time you want to find out how much of something is in another you divide. So 2/(2/7), which is 7. 2nd) Convert 2 into a base of 7 by multipling 2*(7/7)=14/7. Then simply added 2/7 until you get 14/7. So... 2/7+2/7+2/7+2/7+2/7+2/7+2/7=14/7. Now count the number of 2/7 you wrote, and there are 7 of them. So either approach, you get 7 two sevenths are in 2.
It is: 2 because 2 > -7 or -7 < 2
the awnser will be 7 3+3=6+3=9 9-2=7-0=ANS=7
2 2 2 7 7 392 = 2*2*2*7*7 or 23*72
28 = 2 × 2 × 7 = 2² × 7.
2/7 - 4/7 = -2/7
56 = 2*2*2*7 98 = 7*7*2 LCM of 56 = 2*2*2*7*7 or 392
7\25
15/72 1/7:= [(7 * 2)+1]/7= [14 + 1]/7= 15/7 in improper fraction