m(3m + 2)
-6k+7k = 1k or normally k on its own.
5m+3=3m+9 5m+3-3=3m+9-3 5m=3m+6 5m-3m=3m+6-3m 2m=6 (2m)/2=6/2 m=3
-4k-2=10 -4k=10+2 -4k=12 k=-3
4k-7 = 7 4k = 14 k = 3.5 or k = 7/2
2m + 2 = 3m + 4 => 2m-3m = 4-2 => -m = 2 => m= -2
m(3m + 2)
-6k+7k = 1k or normally k on its own.
-3m + 8 = 2 -3m = 2 - 8 -3m = -6 m = -6/-3 m = 2
Without any equality signs the given terms can't be classed as equations.
If by K2 you are not referring to the mountain, the distributive property of multiplication tells us K * 2 = 2 * K.Therefore: K2 + 2K + 4K = 2K + 2K + 4K = 8K
5m+3=3m+9 5m+3-3=3m+9-3 5m=3m+6 5m-3m=3m+6-3m 2m=6 (2m)/2=6/2 m=3
37m squared
18m^2 - 12m + 2 = 2(9m^2 - 6m + 1) you can apply the formula (a - b)^2 = (a^2 - 2ab + b^2) or if you don't remmember it, continue to work: = 2(9m^2 - 3m - 3m + 1) = 2[(9m^2 - 3m) - (3m - 1)] = 2[3m(3m - 1) - (3m - 1)] = 2[(3m - 1)(3m - 1)] = 2(3m - 1)^2
2(3m plus 7) using the distributave property 6m+14. maybe
It's just 3m + 2. Now, if m stands for a particular number, it's 3 times the number, plus two.
3m+2=17 First, subtract 2 to get m on one side. 3m+2-2=17-2 3m=15 Divide by 3 to get m by itself. 3m/3=15/3 m=5 m equals 5.