7x-3=39 7x=42 x=6
Assuming that it is only the x that is being squared. (-21x^2)/39 = (-7x^2)/13
2x + 24 = 9x - 39= 2x + 63 = 9x= 63 = 7x= x = 9
7x^3. That is 7x cubed.... or 7x*7x*7x (where * means multiply). You should get 343x
1
(7x - 4)(7x + 4).
-7x + 6 + 7x - 2 = 4
You can answer this by the method of substitution, which means that you find what one variable equals and you substitute it into the second equation to find the other variable.14x-2y=78; solve for y-2y=78-14x; subtract 14x on both sidesy=-39+7x; divide both sides by -2y=7x-39Substitute 7x-39 for y in the second equation.2x-2(7x-39)=6; solve for x2x-14x+78=6; distribute the -2-12x+78=6-12x=-72; subtract 78 on both sidesx=6; divide both sides by -12Now go back to the first equation and for x, substitute 6. You can either substitute in 14x-2y=78 or the y=7x-39, but it's easier where you already have y isolated.y=7(6)-39y=42-39y=3You got that x=6 and that y=3; therefore, the ordered pair is (6,3).
For X, I assume. 7X - 10 = 4X + 11 subtract 4X from each side 7X - 4X - 10 = 4X - 4X + 11 3X - 10 = 11 add 10 to each side 3X - 10 + 10 = 11 + 10 3X = 21 divide both sides by 3 X = 7 check 7(7) - 10 = 4(7) + 11 49 - 10 = 28 + 11 39 = 39 checks
None. 7x - 1 is not equal to 7x - 7.
-7x + 5 = -9 -7x = -14 7x = 14 x = 2
3/7x + 5 = 87x(3/7x + 5) = 8(7x)3(7x/7x) + (7x)(5) = 8(7x)3 + 35x = 56x3 + 35x - 35x = 56x - 35x3 = 21x3/21 = 21x/211/7 = x