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Possibility of two digit no whose sum is 17. 89 and 98. Reverse of 98 is 89. The no 89 is 9 less than the no 98. So 98 is original no,89 is new no.
1 x 98 = 98 2 x 98 = 196 3 x 98 = 294 4 x 98 = 392 5 x 98 = 490 6 x 98 = 588 7 x 98 = 686 8 x 98 = 784 9 x 98 = 882 10 x 98 = 980
2, 7, and 89 are three prime numbers whose sum is 98.
89+84+90+94+98=455 455/5= 91 91 is the mean.
If x is one of the numbers then the other is (89-x). Both these are positive, so x>0 and 89-x>0 or x<89. Then P(x) = x*(89-x) = 89x-x2 where 0<x<89