An infinite number of ways. 99+9/9 (99+9/9)*9/9 (99+9/9)*99/99 (99+9/9)*999/999 (99+9/9)*9/9*9/9 etc
99
9 x 111 = 999 To simplify the sum, think of it as making 99. 9 x 11 = 99 Then multiply the answer (99) and 11 by ten. That is your answer
999+99+9+9+9
The sum 9 + 99 + 999 + 9999 + 99 999 + .... where the last number to be added consists of nine digits of 9 becomes: (10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ... where the last multiple of 10 has nine zeros. There are nine pairs of brackets altogether. Add the multiples of 10 first and then subtract 9: The digit 1 appears 9 times in the final answer.
An infinite number of ways. 99+9/9 (99+9/9)*9/9 (99+9/9)*99/99 (99+9/9)*999/999 (99+9/9)*9/9*9/9 etc
99 999 999 980 000 000 001
99
99 of them with a remainder of 9
9 x 111 = 999 To simplify the sum, think of it as making 99. 9 x 11 = 99 Then multiply the answer (99) and 11 by ten. That is your answer
999+99+9+9+9
The sum 9 + 99 + 999 + 9999 + 99 999 + .... where the last number to be added consists of nine digits of 9 becomes: (10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ... where the last multiple of 10 has nine zeros. There are nine pairs of brackets altogether. Add the multiples of 10 first and then subtract 9: The digit 1 appears 9 times in the final answer.
999 + 99 = 1098
1000 = 999 + (999 / 999)Due to the rules of BODMAS, the brackets aren't technically necessary.
9, 99, 999 are three.
9999 ÷ 10 = 999.9 Or 999 remainder 9
The LCM of 99 and 999 is 10989