is 567 divisible by both 2 and 9
To find the numbers between 1 and 100 inclusive that are divisible by either 9 or 4, we first determine how many numbers are divisible by 9 and how many are divisible by 4. There are 11 numbers divisible by 9 (9, 18, 27, ..., 99) and 25 numbers divisible by 4 (4, 8, 12, ..., 100). However, we must be careful not to double-count numbers divisible by both 9 and 4 (36, 72). Therefore, the total number of numbers divisible by 9 or 4 between 1 and 100 inclusive is 11 + 25 - 2 = 34.
Yes because you can divide it by 9 and get 25.
To be divisible by 3 and 4 the number must be divisible by 12. 201/12 = 16.75 so the smallest number in the range, divisible by 12, is 17*12 = 204 301/12 = 25.08 so the largest number in the range, divisible by 12, is 25*12 = 300 The number of multiples of 12 is 25 - 16 = 9
Both.
9, yes. 25, no.
No, it is not... For any number to be divisible by 9, the sum of its digits must ALSO divide by 9. In this case, 8+9+4+4=25... 25 is not divisible by 9 !
No, it is not.
9 is divisible by both 3 and 9
9/25 cannot be further simplified. The only factors of 9 are 3,9, and 1. 1 will not help you simplify, and 25 is not divisible by either 3 or 9.
is 567 divisible by both 2 and 9
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not both 10 yes 25 no if divisible exactly by 25 a number ends in 25 50 75 00
To find the numbers between 1 and 100 inclusive that are divisible by either 9 or 4, we first determine how many numbers are divisible by 9 and how many are divisible by 4. There are 11 numbers divisible by 9 (9, 18, 27, ..., 99) and 25 numbers divisible by 4 (4, 8, 12, ..., 100). However, we must be careful not to double-count numbers divisible by both 9 and 4 (36, 72). Therefore, the total number of numbers divisible by 9 or 4 between 1 and 100 inclusive is 11 + 25 - 2 = 34.
Yes because you can divide it by 9 and get 25.
Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.