9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
4m + 9 + 5m - 12 = 42 9m -3 = 42 9m = 42 + 3 9m = 45 m = 5
9m + 9m + 3m + 3m = 24m
9m - 14 = 8 9m = -8 + 14 9m = 6 m = 6/9 = 2/3 or 0.667
8m is between 7m and 9m
Find the area of a trapeziod
5-7m+9m=11
9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
8M - 4M - 6 - 3 + 5M = 82 - 1 9M - 9 = 64 - 1 9M - 9 = 63 9M - 9 +9 = 63 + 9 9M = 72 9M/9 = 72/9 M = 8
The hypotenuse measures 11.4 meters in length.
Ima Say Idk So Yea F It :) 7m x 9m = 63 square metres
4m + 9 + 5m - 12 = 42 9m -3 = 42 9m = 42 + 3 9m = 45 m = 5
3m^2 - 9m = 0 factor out 3m 3m(m - 3) = 0 m = 0 -------- or m = 3 --------
It is 9m^2 - 9 = (3m + 3)*(3m - 3).
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