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What is the answer to 9x15?
135
What are multiples of 9 over 135?
9x15 and above is above
What would the area be with a rectangle wth 9 meters by 15 meters?
9x15 is 135m2
What is sqaure footage of a 9x15 room?
9 feet x 15 feet = 135 square feet.
How many square feet in 9x15?
This answer is found by multiplying the length and the width. This calculation gives you 135 square feet.
What is square footage of a 9x15 room?
That's a peice of cake. All you have to do is multiply 9 by 15. 9 times 15 is 135, so your answer is 135 sqaure feet or 135ft2
What do you consider essential baking equipment?
At least three items are essential. A cookie sheet, 9x9 cake pan, and 9x15 cake pan should be in everyone's kitchen. Additional nice-to-have items are a bread pan, muffin tin and sheet pan.
What are the least common multiples of 9 an 15?
The biggest common divisor of 9 and 15 is 3. To find the least common multiples of 9 an 15 you should multiply these numbers and divide the result by their biggest common divisor. 9x15/3=45
How many 9x15 inch tiles to cover 15 sq meters?
The answer will depend on the shape of the area that you wish to cover. If it is circular, or irregular, you will need to cut or trim a lot of tiles and this will result in significant wastage. If the area is of ideal shape, you will require 173 tiles.
What are the 15 times table?
15x1=15 15x2=30 15x3=45 15x4=60 15x5=75 15x6=90 15x7=105 15x8=120 15x9=135 15x10=150
A recipe for bread says that the ratio of flour to water should be 3 2 if you use 9 cups of flour how much water will you need?
16 ounces = ~ 3 1/2 cups so 6 oz. = ~ 1 1/3 cup
How many feet will take to stop at 60 mph?
That depends on the deceleration applied, in which casetime = 2x45 mph/a = 90/awith a (the deceleration) measured in miles per hour per hour to give the time in hours.If you mean the time that would be taken using the stopping distances in the UK Highway Code, then, assuming a constant deceleration (from the moment the brakes are applied after the thinking distance):The stopping distance at 45 mph is 45 ft (thinking distance) + 101.25 ft (braking distance)[braking distance is speed2 / 20 ft = 452 / 20 ft = 101.25 ft]The thinking distance is travelled at 45 mph, giving:think_time = 45 ft / 45 mph= 45 ft /(45 x 5280 ft / 3600 seconds)= 45 x 3600 / (45 x 5280) seconds= 3600/5280 seconds= 15/22 seconds(This time is constant for all the emergency stopping distances given in the Highway Code.) Two equations of motion can be used to find the stopping time knowing the initial speed and distance (the final speed is zero):final_velocity2 = initial_velocity2 + 2 x acceleration x distancefinal_velocity = 0→ acceleration = - initial_velocity2 / (2 x distance)distance = initial_velocity x time + 1/2 x acceleration x time2→ distance = initial_velocity x time - (1/4 x initial_velocity2 / distance) x time2→ time2 - (4 x distance / initial_velocity) x time + 4 x distance2 / initial_velocity2 = 0→ (time - 2 x distance/initial_velocity)2 = 0→ breaking_time = 2 x distance / initial_velocity= 2 x (101.25 ft) / (45 x 5280 / 3600 ft per sec)= 202.5 x 3600 / (45 x 5280) seconds= 9x15/2x22→ total_stopping_time = 15/22 + 9x15/2x22 seconds= 11x15/2x22 seconds= 15/4 seconds= 33/4 seconds= 3.75 seconds.
