answersLogoWhite

0

Easy. 6000 :P u can also add or subtract 6 from that to get any number and it will always be divisible by six

User Avatar

Wiki User

17y ago

What else can I help you with?

Continue Learning about Other Math

Largest three-digit number that is divisible by 4 5 and 6?

what is the largest three-digit number that is divisible by 4, 5, and 6


What is the rule for a number that is divisible by 4?

If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.


What is the 3 digit number is divisible by 5 6 and 4?

600


What 4-digit number is divisible by 6 and 9?

Try 1008


Is 663 divisible by 2 3 4 5 6 9 10?

By 3 only.It is not divisible by 2, 4, 5, 6, 9 & 10.Division tests:2:If the number is even, ie if the last digit is even (0, 2, 4, 6, 8) it is divisible by 2. 633 is odd (last digit is 3 which is not an even digit), so 633 is not divisible by 2.3:Sum the digits; if the sum is divisible by 3, the original number is divisible by 3. (Can repeat the summing until a single digit remains; if this digit is 3, 6 or 9 (ie divisible by 3) then the original number is divisible by 3.)6 + 6 + 3 = 151 + 5 = 66 is divisible by 3, so 663 is divisible by 3.4:Add the last (units) digit to twice the previous (tens) digit; if this sum is divisible by 4, so is the original number. (Can repeat summing until a single digit remains; if this digit is 4 or 8 (ie divisible by 4) then the original number is divisible by 4.)6 x 2 + 3 = 151 x 2 + 5 = 77 is not divisible by 4, so 663 is not divisible by 4.Note: all multiples of 4 are even; 633 is odd so it cannot be divisible by 4 (the above test does not need to be done).5:The last digit of the number must be 0 or 5. 3 is not 0 nor 5, so 663 is not divisible by 5.6:Number must pass the 2 and 3 tests (above). Fails 2 test (above), so 663 is not divisible by 6.9:Sum the digits; if the sum is divisible by 9, the original number is divisible by 9 (Can repeat the summing until a single digit remains; if this digit is 9 (ie divisible by 9) then the original number is divisible by 9)6 + 6 + 3 = 151 + 5 = 66 is not 9, so 663 is not divisible by 9.10:Last digit must be 0. 3 is not 0, so 663 is not divisible by10.