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The notation Ar 5s2 4d10 5p5 represents the electron configuration of the element arsenic (As), which has an atomic number of 33. This notation indicates that arsenic has 33 electrons distributed among its electron shells. The "Ar" in the notation represents the electron configuration of the noble gas argon, whose electron configuration is [Ne] 3s2 3p6, and serves as a shorthand way to denote the core electrons of the atom. The 5s2 4d10 5p5 portion specifies the distribution of the valence electrons in the outermost energy levels of the arsenic atom.
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How many 5 digit numbers can be formed from the digits 1 2 3 4 5?
5! or 5P5 . A total of 120 series
Q 5th term of a GP is 2 then product of its 9 terms is?
I'll try to answer the question, "If the 5th term of a geometric progression is 2, then the product of its FIRST 9 terms is --?" Given the first term is A and the ratio is r, then the progression starts out... A, Ar, Ar^2, Ar^3, Ar^4, ... So the 5th term is Ar^4, which equals 2. The series continues... Ar^5, Ar^6, Ar^7, Ar^8, ... Ar^8 is the 9th term. The product P of all 9 terms is therefore: P = A * Ar * Ar^2 *...*Ar^8 Collect all the A's P = (A^9)*(1 * r * r^2 ...* r^8) P = A^9 * r^(0+1+2+...+8) There's a formula for the sum of the first n integers (n/2)(n+1), or if you don't know just add it up. 1+2+...+8 = 36 Therefore P = A^9 * r^36 Since 36 is a multiple of 9, you can simplify: P = (Ar^4)^9 Still with me? Remember that Ar^4=2 (a given fact). So finally P = 2^9 = 512. Cute problem.
What is the answer for 9r2s plus 4rs plus 5s2-9s2-9r2-5rs-s2 plus 2r2s plus 4rs plus 2s2?
There is no answer as expressed, since it is not a question. Are you trying to simplify it? 9r2s + 4rs + 5s2 - 9s2 - 9r2 - 5rs - s2 + 2r2s + 4rs + 2s2 = (9 + 2)r2s + (4 - 5 + 4)rs + (5 - 9 - 1 + 2)s2 = 11r2s + 3rs -3s2 = s(11r2 + 3r -3s)
How many canadarms are there?
there ar about 200- 100 -_200
Is 2 10 50 250 1250 geometric?
This is a geometric sequence of the form a, ar, ar^2, ar^3, ... where a is the first term and r is the common ratio.In our case, the first term a = 2, and the common ratio r = 5.The nth term of such a sequence isan = a r^(n -1).
What is the noble configuration of iodine?
(Kr)5s2 4d10 5p5
What is the eletron configuration for iodine?
The electron configuration for iodine is [Kr] 5s2 4d10 5p5.
What is the electronic configuration of Iodine?
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5
What is the electron configuration for iodine?
1s22s22p63s23p64s2 3d104p65s24d105p5
What the electron configuration of I?
long hand: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5 short hand: [Kr] 5s2 4d10 5p5 *remember the number after the letter is written as an exponent*
What is the correct notation for iodine?
The correct chemical notation for iodine is I.
Is the electron configuration kr 5s2 4d10 5p5 valid?
No, the electron configuration is incorrect. The correct electron configuration for an element with 52 electrons would be Kr 5s2 4d10 5p6.
Abbreviated electron configuration for Bromine?
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5 or [Ar] 4s2 3d10 4p5
What is the Electron configurations iodine?
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5
What the electron configuration of iodine?
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6
N ion X- has the electron configuration Kr5s2 4d10 5p5. What is element X?
The element X with the electron configuration Kr5s2 4d10 5p5 is Iodine (I).
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3 5s2 4d10 5p5 What is the mistake to this configuration and why andwhat element is it and what is the correct configuration?
The mistake in this electron configuration is in the 5p subshell, where it shows 5p5 instead of 5p6. The correct element for this configuration is Xenon (Xe). The correct electron configuration for Xenon is [Kr] 5s2 4d10 5p6.
