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What is Ar 5s2 4d10 5p5?

Updated: 4/28/2022
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what is 5s2 4d10 5p5

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Q: What is Ar 5s2 4d10 5p5?
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How many 5 digit numbers can be formed from the digits 1 2 3 4 5?

5! or 5P5 . A total of 120 series


Q 5th term of a GP is 2 then product of its 9 terms is?

I'll try to answer the question, "If the 5th term of a geometric progression is 2, then the product of its FIRST 9 terms is --?" Given the first term is A and the ratio is r, then the progression starts out... A, Ar, Ar^2, Ar^3, Ar^4, ... So the 5th term is Ar^4, which equals 2. The series continues... Ar^5, Ar^6, Ar^7, Ar^8, ... Ar^8 is the 9th term. The product P of all 9 terms is therefore: P = A * Ar * Ar^2 *...*Ar^8 Collect all the A's P = (A^9)*(1 * r * r^2 ...* r^8) P = A^9 * r^(0+1+2+...+8) There's a formula for the sum of the first n integers (n/2)(n+1), or if you don't know just add it up. 1+2+...+8 = 36 Therefore P = A^9 * r^36 Since 36 is a multiple of 9, you can simplify: P = (Ar^4)^9 Still with me? Remember that Ar^4=2 (a given fact). So finally P = 2^9 = 512. Cute problem.


What is the answer for 9r2s plus 4rs plus 5s2-9s2-9r2-5rs-s2 plus 2r2s plus 4rs plus 2s2?

There is no answer as expressed, since it is not a question. Are you trying to simplify it? 9r2s + 4rs + 5s2 - 9s2 - 9r2 - 5rs - s2 + 2r2s + 4rs + 2s2 = (9 + 2)r2s + (4 - 5 + 4)rs + (5 - 9 - 1 + 2)s2 = 11r2s + 3rs -3s2 = s(11r2 + 3r -3s)


How many canadarms are there?

there ar about 200- 100 -_200


Is 2 10 50 250 1250 geometric?

This is a geometric sequence of the form a, ar, ar^2, ar^3, ... where a is the first term and r is the common ratio.In our case, the first term a = 2, and the common ratio r = 5.The nth term of such a sequence isan = a r^(n -1).