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JudyThe notation Ar 5s2 4d10 5p5 represents the electron configuration of the element arsenic (As), which has an atomic number of 33. This notation indicates that arsenic has 33 electrons distributed among its electron shells. The "Ar" in the notation represents the electron configuration of the noble gas argon, whose electron configuration is [Ne] 3s2 3p6, and serves as a shorthand way to denote the core electrons of the atom. The 5s2 4d10 5p5 portion specifies the distribution of the valence electrons in the outermost energy levels of the arsenic atom.
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How many 5 digit numbers can be formed from the digits 1 2 3 4 5?
5! or 5P5 . A total of 120 series
Q 5th term of a GP is 2 then product of its 9 terms is?
I'll try to answer the question, "If the 5th term of a geometric progression is 2, then the product of its FIRST 9 terms is --?" Given the first term is A and the ratio is r, then the progression starts out... A, Ar, Ar^2, Ar^3, Ar^4, ... So the 5th term is Ar^4, which equals 2. The series continues... Ar^5, Ar^6, Ar^7, Ar^8, ... Ar^8 is the 9th term. The product P of all 9 terms is therefore: P = A * Ar * Ar^2 *...*Ar^8 Collect all the A's P = (A^9)*(1 * r * r^2 ...* r^8) P = A^9 * r^(0+1+2+...+8) There's a formula for the sum of the first n integers (n/2)(n+1), or if you don't know just add it up. 1+2+...+8 = 36 Therefore P = A^9 * r^36 Since 36 is a multiple of 9, you can simplify: P = (Ar^4)^9 Still with me? Remember that Ar^4=2 (a given fact). So finally P = 2^9 = 512. Cute problem.
What is the answer for 9r2s plus 4rs plus 5s2-9s2-9r2-5rs-s2 plus 2r2s plus 4rs plus 2s2?
There is no answer as expressed, since it is not a question. Are you trying to simplify it? 9r2s + 4rs + 5s2 - 9s2 - 9r2 - 5rs - s2 + 2r2s + 4rs + 2s2 = (9 + 2)r2s + (4 - 5 + 4)rs + (5 - 9 - 1 + 2)s2 = 11r2s + 3rs -3s2 = s(11r2 + 3r -3s)
How many canadarms are there?
there ar about 200- 100 -_200
Is 2 10 50 250 1250 geometric?
This is a geometric sequence of the form a, ar, ar^2, ar^3, ... where a is the first term and r is the common ratio.In our case, the first term a = 2, and the common ratio r = 5.The nth term of such a sequence isan = a r^(n -1).
