360.
6 + (the quotient of a number and 4) =6 + (number ÷ 4)=6 + (N÷4) =⁶/₁ + ⁿ/₄ =²⁴/₄ + ⁿ/₄ =²⁴ⁿ/₄ =24n ÷ 4 =6n ÷ 1 =6n
(n/4)2, where n is a number.
if the quotient of -20 and 4 is decreased by 3
A single number cannot have a sum, or a quotient.
360.
It is: 20/5 = 4 which is the quotient
7 subtracted from the quotient of a number and 2 is a -6
n-4
6 + (the quotient of a number and 4) =6 + (number ÷ 4)=6 + (N÷4) =⁶/₁ + ⁿ/₄ =²⁴/₄ + ⁿ/₄ =²⁴ⁿ/₄ =24n ÷ 4 =6n ÷ 1 =6n
(n/4)2, where n is a number.
X / ( y + 4 )
if the quotient of -20 and 4 is decreased by 3
let X = number quotient = x/4 x/4 + 9 = 12 x/4 = 3 x = 12
A single number cannot have a sum, or a quotient.
4 over n
4 - 8/x