To solve this expression, we need to follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right). In this case, we first need to multiply XXIX (29) by LI (51) to get 29 * 51 = 1479. Then, we add XX (20) to this result to get 1479 + 20 = 1499. Therefore, XX plus XXIX times LI equals 1499.
IX (9) + XV (15) + XX (20) = XLIV (44)
Well, isn't that a happy little question! When you divide CD by XX, you're essentially breaking CD into XX equal parts to see how many times XX fits into CD. It's like sharing a big, beautiful painting with XX friends to make sure everyone gets a fair share of the joy. Just remember to take your time, enjoy the process, and let those happy little numbers guide you to a peaceful solution.
Assuming the missing number as XX + 53 = 180X = 180 - 53X = 127127 is the Answer
8x = 90Therefore, 90/8 = xx = 11.25.
This question can't be answered as asked because IXX isn't valid in any known numbering system. The nearest valid number is XIX in the Roman system, or 19 in our system. Showing my working is not possible because it was done in my head. If you want to know how you could do it in your head (or on paper if you need to show it to your teacher) here it is. * XIXII can be re-written as XXII - (II x XIX) - I. * XXII = CD * - (II x XIX) - I = - XXXIX * CD - XXXIX = CCCLXI * XIXII = CCCLXI . . . . . QEC ( quod erat calculandum. )
29 = XXIX (XX= 20, IX = 9)
Say x is 5 so 5 + 5 = 10 where as 5 times 5 = 25 The difference is "x + x" is a addition and "xx" (x times x) is a multiplication.
3xx + 2 + xx + 4 = 4xx + 6 = 2(2xx + 3)
IX (9) + XV (15) + XX (20) = XLIV (44)
In today's modern configuration they are: XX, XXI, XXII, XXIII, XXIV, XXV, XXVI, XXVII, XXVIII, XXIX, XXX
xvi, xvii, xviii, xix, xx, xxi, xxii, xxiii, xxiv, xxv, xxvi, xxvii, xxviii, xxix, xxx
In today's terms they are: XX, XXI, XXII, XXIII, XXIV, XXV, XXVI, XXVII, XXVIII, XXIX and XXX. But during the times of the Romans 24 and 29 would probably have been written as XXIIII and XXVIIII respectively.
IXX (19) squared = -I(-I+XX)+XX(-I+XX) Multiplying out brackets = +I-XX-XX+CCCC Collecting like terms = -XXXX+CCCC+I (401-40) Then when simplified = CCCLXI (361) which is the correct answer. Remember that in maths a minus number multiplied by a minus number produces a plus number. Thus -I times -I is +I. David Gambell, Merseyside, England.
To write 20 in Roman numerals, you would use XX. To write 30, you would use XXX. Therefore, to write 20-30 in Roman numerals, you would write XX-XXX.
x=5 so it's 55+55= 110
4x plus 7 plus 3x equals 19 plus xx = 2
xx+3x+7=6x+18 xx+3x+7-(6x+18)=6x+18-(6x+18) xx-3x-11=0 Factors of -11: 1,-11 -1,11 Doesn't factor evenly, use quadratic