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Q: What is XX plus XXIX times LI?

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IX (9) + XV (15) + XX (20) = XLIV (44)

Assuming the missing number as XX + 53 = 180X = 180 - 53X = 127127 is the Answer

8x = 90Therefore, 90/8 = xx = 11.25.

This question can't be answered as asked because IXX isn't valid in any known numbering system. The nearest valid number is XIX in the Roman system, or 19 in our system. Showing my working is not possible because it was done in my head. If you want to know how you could do it in your head (or on paper if you need to show it to your teacher) here it is. * XIXII can be re-written as XXII - (II x XIX) - I. * XXII = CD * - (II x XIX) - I = - XXXIX * CD - XXXIX = CCCLXI * XIXII = CCCLXI . . . . . QEC ( quod erat calculandum. )

x times x, (x)(x), or x squared

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29 = XXIX (XX= 20, IX = 9)

Xx, xxi, xxii, xxiii, xxiv, xxv, xxvi, xxvii , xxviii, xxix, xxx

3xx + 2 + xx + 4 = 4xx + 6 = 2(2xx + 3)

Say x is 5 so 5 + 5 = 10 where as 5 times 5 = 25 The difference is "x + x" is a addition and "xx" (x times x) is a multiplication.

IX (9) + XV (15) + XX (20) = XLIV (44)

In today's modern configuration they are: XX, XXI, XXII, XXIII, XXIV, XXV, XXVI, XXVII, XXVIII, XXIX, XXX

xvi, xvii, xviii, xix, xx, xxi, xxii, xxiii, xxiv, xxv, xxvi, xxvii, xxviii, xxix, xxx

In today's terms they are: XX, XXI, XXII, XXIII, XXIV, XXV, XXVI, XXVII, XXVIII, XXIX and XXX. But during the times of the Romans 24 and 29 would probably have been written as XXIIII and XXVIIII respectively.

IXX (19) squared = -I(-I+XX)+XX(-I+XX) Multiplying out brackets = +I-XX-XX+CCCC Collecting like terms = -XXXX+CCCC+I (401-40) Then when simplified = CCCLXI (361) which is the correct answer. Remember that in maths a minus number multiplied by a minus number produces a plus number. Thus -I times -I is +I. David Gambell, Merseyside, England.

x=5 so it's 55+55= 110

4x plus 7 plus 3x equals 19 plus xx = 2

xx+3x+7=6x+18 xx+3x+7-(6x+18)=6x+18-(6x+18) xx-3x-11=0 Factors of -11: 1,-11 -1,11 Doesn't factor evenly, use quadratic