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This is a "least common multiple" problem. Any number that is divisible by the LCM of these integers is divisible by all of them separately.
2, 3, and 5 are primes (n1) but 9 is 3², so the LCM is 2 × 5 × 3² = 90
The four digit numbers divisible by 90 begin with 1080 (90 × 12) and continue through 9990 (90 × 111) a total of 100 numbers.
1080 1170 1260 1350 1440 1530 1620 1710 1800 1890 1980,
2070 2160 2250 2340 2430 2520 2610 2700 2790 2880 2970
3060 3150 3240 3330 3420 3510 3600 3690 3780 3870 3960
4050 4140 4230 4320 4410 4500 4590 4680 4770 4860 4950
5040 5130 5220 5310 5400 5490 5580 5670 5760 5850 5940
6030 6120 6210 6300 6390 6480 6570 6660 6750 6840 6930
7020 7110 7200 7290 7380 7470 7560 7650 7740 7830 7920
8010 8100 8190 8280 8370 8460 8550 8640 8730 8820 8910
9000 9090 9180 9270 9360 9450 9540 9630 9720 9810 9900 9990
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What is a four digit number that is divisible by 3 and 2?
1002 is the smallest 4 digit number divisible by 3 and 2.
What is the converse inverse and contrapositive If every digit of a number is divisible by 3 then the number is divisible by 3?
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I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
What is the smallest 4 digit number that is divisible by 2 and 3?
1000 is the smallest 4 digit number but of the two factors, it is only divisible by 2. As 999 is obviously divisible by 3 then 999 + 3 = 1002 is also divisible by 3 and, as an even number, is also divisible by 2. The answer is 1002
Is 552 divisible by 6?
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