That's an arbitrary question. You can make any expression you want that includes 80 somewhere and simplify it. Then substitute x for 80 on the left hand-side and set this equal to the expression you found. For example, I came up with the following using this method:
(x+100)2/(sqrt(x)+3)=(129600*sqrt(10)-97200)/71
Expressed as an equation, this is equal to 80/b.
For the equation 80% of what number equals 40, the unknown number is 50.
x = 79 + 1 is one of the infinite number of such equations.
The result of the equation - 80 plus 90 plus 60 plus 80, is found as follows; 80 + 90 + 60 + 80 = ( 80 + 90 ) + 60 + 80 = 170 + ( 60 + 80 ) = 170 + 140 = 310 Answer = 310
The result of the equation - 130 plus 80 plus 20 plus 80, is found as follows;130 + 80 + 20 + 80= ( 130 + 80 ) + 20 + 80= 210 + ( 20 + 80 )= 210 + 100= 310Answer = 310
There is no such thing. Take any equation - you can always make it still more complicated, by some basic algebraic manipulation.
Expressed as an equation, this is equal to 80/b.
5x = 80
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
No
44 = 80*x
(x -20)5 = 0 -- will look more complicated if you multiply it out and transpose some of the terms.
You have to write an equation for this. When you do percents, you always have to convert them to decimals. (Therefore, 80% is .80 as a decimal) .80x = 8 Divide both sides of the equation by .8 and you'll get x = 10
"10 + 50 = 80" is an incorrect equation.
-(x)/(16)=5Multiply each term in the equation by 16.-(x)/(16)*16=5*16Simplify the left-hand side of the equation by canceling the common terms.-x=5*16Multiply 5 by 16 to get 80.-x=80Multiply each term in the equation by -1.-x*-1=80*-1Multiply -x by -1 to get x.x=80*-1Multiply 80 by -1 to get -80.x=-80
Use the quadratic equation formula to find the solutions to this equation.
For the equation 80% of what number equals 40, the unknown number is 50.