The final sum is 9
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
If the digit sum of a number is 9 then it is divisible by 9
10 9+9+1 = 19 1+9=10
If the digit sum of any number from 1 to 10,000 add up to 9 then that number is divisible by 9 as for example 7641 is divisible by 9 because the final digit sum is 9 and so 7641/9 = 849
The final sum is 9
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
300
If the digit sum of a number is 9 then it is divisible by 9
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
9
I'm a five digit numberThere are lots of solutions to this.Example:9 + 9 + 9 + 8 + 5 = 40
999 + 9 = 1008
The sum of the digits of 171 is 9.
If the digit sum of a number adds up to 9 then it is divisible by 9.
I think the answer is 612!1 (tens digit) which is odd is half of 2 (hundreds digit) and the sum is (6+1+2=9).
10 9+9+1 = 19 1+9=10