Two Numbers consisting only of ones that when multiplied or added equal the same number are 11, and 1.1
6x + 18 = 4 - x 7x + 18 = 4 7x = -14 x = -2
The number 2, in base 4 arithmetic.
Let the number be x: 2(2x+4) = 3x+4 4x+8 = 3x+4 4x-3x = 4-8 x = -4
20
Because 51 is an odd number, it cannot be totalled by adding the same number twice.
Two Numbers consisting only of ones that when multiplied or added equal the same number are 11, and 1.1
Suppose the number is x. Then 32 + 6x = 2x Subtract 6x from both sides: 32 = -4x Divide both sides by -4: -8 = x
6x + 18 = 4 - x 7x + 18 = 4 7x = -14 x = -2
The number 2, in base 4 arithmetic.
There are two answers either 8x + 4 or 7x + 4
A box that 4 sides on all sides that when added up from any angle or side will equal the same number.
They are the same value. Any amount of zeros added to the number before the first digit will still make the number equal. For example, 65 and 00000000065 are equal.
4(8+2x)=5x+1132+8x=5x+118x-5×=11-323x=-213 3=-7Therefore the number is -7
You set up an equation with each condition on either side of the equal sign. If I have the problem correct: (x + 3 + 3)3 = -x + 2. Simplify: (x + 6)3 = -x + 2 4x + 18 = 2 4x = -16 x = -4
Let the number be x: 2(2x+4) = 3x+4 4x+8 = 3x+4 4x-3x = 4-8 x = -4
((2n + 8)) x 5 = 6n + 12ie 10n + 40 = 6n + 124n = -28n = -7(both equations total -30)