asking how to solve
if the quotient of -20 and 4 is decreased by 3
7x - 8 = 3x + 4 4x - 8 = 4 4x = 12 x = 3 Check it. 21 - 8 = 9 + 4 It checks.
The number = 9Working:n - 5 = 13 - n(+ 5 on both sides)n = 18 - n(+ n on both sides)n + n = 18= 2n = 18(divide both sides by 2)n = 9So...9 - 5 = 13 - 9(9 - 5 = 4)(13 - 9 = 4)
From least tor greatest, -15, -12, -9, -4
-22, because if you subtract from a negative, the number gets higher.
if the quotient of -20 and 4 is decreased by 3
the product of -6 and a number, x, decreased by 9, is -33. what is the number?
The inequality for a number ( x ) decreased by two being at most four can be expressed as ( x - 2 \leq 4 ). The condition of being at least nine translates to ( x - 2 \geq 9 ). Therefore, the complete set of inequalities is ( x - 2 \leq 4 ) or ( x - 2 \geq 9 ). Simplifying these gives us ( x \leq 6 ) or ( x \geq 11 ).
The number is -9 because (-9/-9) -18 = -17
1035
The least common multiple of any set of positive integers is 1.
Least is 03469 Greatest is 96430
11-9=v
180 is divisible by 2, 3, 4, 5, 9, and 10.
7x - 8 = 3x + 4 4x - 8 = 4 4x = 12 x = 3 Check it. 21 - 8 = 9 + 4 It checks.
i really need help
y = x-9 here y is the new number when the original number x is decreased by 9