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All multiples of the lowest common multiple of them are divisible by all of them:
lcm(11, 9, 6, 7) = 1386
→ numbers divisible by all of them are:
1386, 2772, 4158, 5544, 6930, 8316, 9702, 11088, 12474, 13860, 15246, 16632, 18018, 19404, 20790, 22176, 23562, 24948, 26334, 27720, 29106, 30492, 31878, 33264, 34650, 36036, 37422, 38808, 40194, 41580, 42966, 44352, 45738, 47124, 48510, 49896, 51282, 52668, 54054, 55440, 56826, 58212, 59598, 60984, 62370, 63756, 65142, 66528, 67914, 69300, 70686, 72072, 73458, 74844, 76230, 77616, 79002, 80388, 81774, 83160, 84546, 85932, 87318, 88704, 90090, 91476, 92862, 94248, 95634, 97020, 98406, 99792, 101178, 102564, 103950, 105336, 106722, 108108, 109494, 110880, 112266, 113652, 115038, 116424, 117810, 119196, 120582, 121968, 123354, 124740, 126126, 127512, 128898, 130284, 131670, 133056, 134442, 135828, 137214, 138600, ...
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What is the smallest number that is divisible by 5 6 and 7?
The smallest number that is divisible by 5, 6, and 7 is 210.
What is the smallest number that is divisible by 5 6 7 and 8?
840 is the smallest number that is divisible by 5 6 7 and 8.
What is the smallest number which is divisible by 7 and 6 and has two odd digits?
To find the smallest number divisible by 7 and 6 with two odd digits, we need to consider the least common multiple (LCM) of 7 and 6, which is 42. The smallest two-digit odd number is 11. Therefore, the smallest number that meets all these criteria is 11 x 42, which equals 462.
Is 5278 divisible by3?
Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number
What numbers are divisible by 6 and 7?
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
