All multiples of the lowest common multiple of them are divisible by all of them:
lcm(11, 9, 6, 7) = 1386
→ numbers divisible by all of them are:
1386, 2772, 4158, 5544, 6930, 8316, 9702, 11088, 12474, 13860, 15246, 16632, 18018, 19404, 20790, 22176, 23562, 24948, 26334, 27720, 29106, 30492, 31878, 33264, 34650, 36036, 37422, 38808, 40194, 41580, 42966, 44352, 45738, 47124, 48510, 49896, 51282, 52668, 54054, 55440, 56826, 58212, 59598, 60984, 62370, 63756, 65142, 66528, 67914, 69300, 70686, 72072, 73458, 74844, 76230, 77616, 79002, 80388, 81774, 83160, 84546, 85932, 87318, 88704, 90090, 91476, 92862, 94248, 95634, 97020, 98406, 99792, 101178, 102564, 103950, 105336, 106722, 108108, 109494, 110880, 112266, 113652, 115038, 116424, 117810, 119196, 120582, 121968, 123354, 124740, 126126, 127512, 128898, 130284, 131670, 133056, 134442, 135828, 137214, 138600, ...
The smallest number that is divisible by 5, 6, and 7 is 210.
840 is the smallest number that is divisible by 5 6 7 and 8.
To find the smallest number divisible by 7 and 6 with two odd digits, we need to consider the least common multiple (LCM) of 7 and 6, which is 42. The smallest two-digit odd number is 11. Therefore, the smallest number that meets all these criteria is 11 x 42, which equals 462.
Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number
7 can't be divided into any number. and ask you teacher for the answer as well. 42 is divisible by 6 and 7. There are many numbers that are divisible by 7 eg 42, 21. 84, 140,
The smallest number divisible by 2 3 4 5 6 7 9 10 and 11 is 13,860.
The smallest number that is divisible by 5, 6, and 7 is 210.
11
840 is the smallest number that is divisible by 5 6 7 and 8.
A prime number is one that has only two factors: one and itself.You can tell if a number is prime quickly by using the Laws of Divisibility:Numbers that end in 0, 2, 4, 6, and 8 are divisible by 2.If the sum of a number's digit is divisible by 3, the number itself is divisible by 3.If the last two digits of a number are divisible by 4, the number itself is divisible by 4.If a number ends in 0 or 5, it is divisible by 5.If a number is divisible by both 2 and 3, it is divisible by 6.If you double the last digit and subtract it from the rest of the number and the answer is 0 or divisible by 7, it is divisible by 7. For example, 4364: 4 doubled is 8. 436 - 8 = 424. You still cannot readily tell if the number is divisible by 7, so you can do it again: 4 doubled is 8. 42 - 8 = 34. 34 is not divisible by 7 so 436 is not divisible by 7If the last three digits of a number are divisible by 8, the number itself is divisible by 8.If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9.If a number ends with 0, it is divisible by 10.If you add every other digit and then subtract the rest of the digits and the answer is 0 or is divisible by 11, the number itself is divisible by 11. For example: 1364: 1+ 6 = 7 and 7 - 3 - 4 = 0. The number is divisible by 11.If the number is divisible by 3 and 4, it is divisible by 12.There are more divisibility rules that can be used for large numbers.
To find the smallest number divisible by 7 and 6 with two odd digits, we need to consider the least common multiple (LCM) of 7 and 6, which is 42. The smallest two-digit odd number is 11. Therefore, the smallest number that meets all these criteria is 11 x 42, which equals 462.
No.
The smallest number divisible by 5 7 9 11 13 and 15 is 45,045.
Well, honey, any number that doesn't end in 0, 2, 3, 4, 6, or 8 is not divisible by 6. So, basically, any odd number or any number that doesn't have 2 or 3 as a factor won't be cozy with 6. Just remember, 6 is a bit picky when it comes to sharing its love with other numbers.
LCM(2, 7, 11) = 154.
To find out if 1859 is a prime number, use the rules of division:1859 is not an even number, so it is not divisible by 2.The digits of 1859 add up to a number that is divisible by 3, so it is not divisible by 3.The last two digits (59) is not divisible by 4, so neither is 1859.The last digit is not 5, so it is not divisible by 5.1859 is not divisible by 2 and it is not divisible by 3, so it is not divisible by 6.When you double the last digit (9 doubled is 18), and subtract that number from the rest of the number (859 - 18 = 841), if the answer is 0 or divisible by 7, the number itself is divisible by 7. If you can't readily tell if the number is divisible by 7, you can do the steps again. Starting with 841, doubling the 1 is still 1, so take 1 away from 84 to get 83. 83 is not divisible by 7, so neither is 1859.The last three digits (859) are not divisible by 8, so 1859 is not divisible by 8.If the sum of the digits is divisible by 9, the number is divisible by 9. The sum of the digits is 23, which is not divisible by 9.1859 does not end with a 0, so it is not divisible by 10.If the sum of every second digit (8 + 9) minus the sum of the other digits (1 + 5) equals 0 or is divisible by 11, the number itself is divisible by 11. 17 - 6 = 11, so 1859 is divisible by 11.Since 1859 is divisible by 11, it is a composite number (a number that has at least three factors: 1, the number itself, and at least one oher factor).
210