(root 2)/3
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The sum, or difference, of two irrational numbers can be rational, or irrational. For example, if A = square root of 2 and B = square root of 3, both the sum and difference are irrational. If A = (1 + square root of 2), and B = square root of 2, then, while both are irrational, the difference (equal to 1) is rational.
Oh, dude, irrational numbers are like those numbers that can't be expressed as fractions, you know? So, between 1 and 100, you've got classics like the square root of 2, square root of 3, and pi, just chilling there, being all irrational and stuff. It's like they're rebels in the math world, refusing to conform to the whole "I can be written as a simple fraction" thing.
In a calculator pi^(1/2) = pi^(0.5) = 3.141592.....^ (1/2) = 1.772453851.... Since 'pi' is an irrational number, then the square root of 'pi' is also irrational .
No; the square root of any rational number squared is that rational number. Examples: √(2^2) = √4 = 2. √((1/2)^2) = √(1/4) = 1/2
The even-ness of the number is not relevant. The square root of 1, 4, 9 and 16 are 1, 2, 3 and 4, because 1*1 is 1, 2*2 is 4, 3*3 is 9 and 4+4 is 16. The numbers in between are irrational: The square root of 2 is 1.4 and a bit, the square root of 3 is 1.7 and a bit.