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With a signed integer, the top bit is used to hold the sign of the number, so that the range of numbers that can be held is -(2number_of_bits-1) to 2number_of_bits-1 -1, whereas with an unsigned integer, all the bits are used to store the number which will always be positive and so the range is 0 to 2number_of_bits -1.
For example, with 16 bits, a signed integer has the range -(215) to 215 -1 = -32768 to 32767 whereas an unsigned integer has the range 0 to 216 -1 = 0 to 65535.
The point in particular to note is how the numbers (bit patterns) with the top bit set are interpreted: with unsigned ints they are greater than those without the top bit set (eg 0xffff = 65535 > 0x7fff = 32767), but with signed ints they are less (eg 0xffff = -1 < 0x7fff = 32767).
I'm not sure about the significance of declaring a constant as unsigned (having never used one), but at a guess I would say it's to tell the compiler that the bit pattern is an unsigned bit pattern and to throw up a warning (or error) if it's used with a signed bit pattern, eg if used in a comparison with a signed int - ie an aid to cutting down on bugs by ensuring that things are only used for their intended purpose.
What else can I help you with?
What is the maximum number in unsigned 16-bits?
65536
Perform sutraction with unsigned decimal form by taking 10's complement of the sutahend 5250-1321?
perform subtraction with the following unsigned decimal number by taking the 10's complement of the subtrahend 5250-1321
The twos complement of 11001101 is?
00110011 is the 2's complement for this unsigned number and 10110011 if this is a signed number
2's complement of a binary number in c language?
/* note that neither of these functions have been tested, so there may be typos and the like *//* if you're looking to return a real value: */unsigned int complement(unsigned int value){unsigned int returnvalue = 0;while(value){returnvalue = 1;}return returnvalue;}/* if you're looking for a string representing the binary number: */char *complement(unsigned int value){int numchars = 8 * sizeof(unsigned int);int n;char *returnvalue = malloc((numchars + 1) * sizeof(char));for(n = 0; n < numchars; n++){if(value & (1
What is the binary range in decimal of a byte?
Nobody knows what you are talking about, but if you mean what the biggest number is in a byte, it is 255 or 127. The former is only for unsigned, while the latter is the maximun if the byte is signed. If you mean how many numbers can be represented, it is 256 or 128. Again, the former is if it is unsigned and the latter is if it is signed.
