b/2=2ab/+b means112.5
This cannot be solved. If you have 2 unknowns (a,b) then you must have 2 equations.
a/b = 1 so a = b. Then a b = q implies that a = b = q/2 So ab = (q/2)*(q/2) = q2/4
4/b-3 + 3/b = -2b/b-3 b = 1 or b = -4.5
26 = 3b - 2 - 7b 28 = -4b b = -7
-40
b/2=2ab/+b means112.5
b divided by 2
A^2 + b = 7 A + B^2 =11 -------------- A=2 and B=34(2^2) + 3 = 7 2 + 9(3^2) = 11
This cannot be solved. If you have 2 unknowns (a,b) then you must have 2 equations.
80 divided by four equals 20.
Commutative, not communtative The mathematical property of being able to change the order of the numbers and not change the answer. A plus B equals B plus A (1 plus 3 equals 4, 3 plus 1 equals 4) A times B equals B times A (2 times 5 equals 10, 5 times 2 equals 10) Addition and multiplication are commutative operators A minus B is not necessarily equal to B minus A (6 minus 4 equals 2, 4 minus 6 equals minus 2) A divided B is not necessarily equal to B divided A (9 divided by 3 equals 3, 3 divided by 9 equals one-third) Subtraction and division are not commutative operators
a/b = 1 so a = b. Then a b = q implies that a = b = q/2 So ab = (q/2)*(q/2) = q2/4
Because there is no way to define the divisors, the equations cannot be evaluated.
No, log3 to the base 2 is irrational.
A/b = 50/88 = 0.5681818181
x=2ab+7 x= 2(3)(5) +7 x=30+7 x=37