-5
5d + 2(3d) 5d + 6d 11d
AB = 2 x 4 (8) C = 3 D = 5
2+2+2+10+5+5+5+20+20+20+20+20+20=151
the answer is a
-d + 2 = 5(- 2 from both sides)-d = 3(x both sides by -1)d = -3
d = 2
If: d+7 = 5 Then: d = -2 by subtracting 7 from both sides
D = b²-4ac a=2, b=5, c=4 D=5²-4(2*4) D=25-4(8) D=25-32 D=-7■
It is an equation and the value of d is 2
-5
5d + 2(3d) 5d + 6d 11d
AB = 2 x 4 (8) C = 3 D = 5
int a=2, b=3, c=4, d=5; printf ("%d/%d + %d/%d = %d/%d\n", a, b, c, d, a*d+b*c, b*d);
Call the unknown value of (x - y) d. Then x = y + d; from the problem statement, y + d + 2(y + d) +5 = y + 2y; expanding yields y + d + 2y + 2d + 5 = y + 2y; (y + 2 y) can be subtracted from both sides and terms in d collected to result in 3d + 5 = 0; 3d = -5; d = -5/3.
2+2+2+10+5+5+5+20+20+20+20+20+20=151
Just realize that multiplication is repeated addition. So you have 6 twos and 5 fives. that is 12+25 and now add 55 The total is 92