Any of its factors including itself are evenly divisible into 1500
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The factors of 1,500 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 25, 30, 50, 60, 75, 100, 125, 150, 250, 300, 375, 500, 750, 1500.
There are 39 natural numbers between 1,000 and 1,500, inclusive, that are divisible by 13.
1260 / 1500 can be reduced. Both numbers end in a zero, so we can see that both are divisible by 10. This gives us 126 / 150. We know that both of these are also divisible by two because they end in even numbers; this gives us 63 / 75. 75 is divisible by 1, 3, 5, 15, 25 and itself; 63 is divisible by 1, 3, 7, 9, 21, and itself. Dividing by 3 gives us 21 / 25, which does not reduce any further.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
It's false because we have numbers that is divisible by 10 but not divisible by 5 and vice versa, we have numbers that is divisible by 10 but not divisible by 5.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.