The domain of f is x is R (if imaginary roots are permitted, and there is nothing in the question to suggest otherwise).
The domain of g is R excluding x = 5
So the domain of f + g is R excluding x = 5
and the domain of f/g is R excluding x = 0
X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12
Plus or minus 3i.
plus or minus 33
square root -5 minus 14 or - square root -5 minus 14
?
plus or minus. You see it often with square roots. The square root of 9 is plus or minus 3.
No, it becomes a plus, since minus x minus = plus
a square minus b square
X2+5x-6. a=1, b=5, and c=-6 The formula is: -b plus or minus the square root of b squared minus 4ac all over 2a. -b+square root of b2-4ac ---- 2a -5 plus or minus the square root of 5 squared minus 4(1)(-6) -5 plus or minus the square root of 25-4(-6) -5 plus or minus the square root of 25+24 -5 plus or minus the square root of 49 -5 plus or minus 7 Here is where you split into two different answers: Number 1: -5 plus 7= 2 Number 2: -5 minus 7= -12 Your answer is X=2, -12
x equals negative b plus or minus the square root of b squared minus 4bc over 2a
negative b plus or minus the square root of b minus 4 times ac all over 2 a
negative b plus or minus the square root of b squared minus 4AC all over 2 A
plus or minus 15
A square root.
If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A
The quadric equation is: negative b plus or minus the square root of b squared minus 4ac all over(divided by) 2a
7m2 + 6.5n - 4n + 2.5m2 - n = 9.5m2 + 1.5n