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What number is half of 61?
Half of 61 is 30.5
What is half of 122?
122/2 = 61
What number is halfway between 53 and 61?
Half way between 53 and 61 is (53 + 61) ÷ 2 = 57(53 + 61) / 2 = 114/2 = 5753+61 / 2114/257 is the answer
What is halfway between 53 and 61?
The difference is 8. So add half of 8 to 53 : 53 + 4 = 57. Or subtract half of 8 from 61 : 61 - 4 = 57. Either way, the halfway point is 57.
What is the value of a 1961 US Half Dollar with the D mint mark which is 90 percent silver?
At current silver prices, a '61 Franklin half is worth just under $10.
What number is one half of 61?
30½ is half of 61 (or 30.5)
What number is half of 61?
Half of 61 is 30.5
What is half of 122?
122/2 = 61
What number is halfway between 53 and 61?
Half way between 53 and 61 is (53 + 61) ÷ 2 = 57(53 + 61) / 2 = 114/2 = 5753+61 / 2114/257 is the answer
What is halfway between 53 and 61?
The difference is 8. So add half of 8 to 53 : 53 + 4 = 57. Or subtract half of 8 from 61 : 61 - 4 = 57. Either way, the halfway point is 57.
How do you change 61 and half percent to a fraction?
61.5/100
What number is half the way between 53 and 61?
57
How do you write one and one half percent?
Six and One Half Percent is written as 61/2%
How many half inch gumballs fit in a quart mason jar?
61
How do you write Six and One Half Percent?
Six and One Half Percent is written as 61/2%
How much Cu-61 (half-life about 3 hours) would remain from a 2 mg sample after 6 hours?
The half-life of Cu-61 is approximately 3 hours, meaning after each half-life, half of the remaining substance decays. After 6 hours, which is two half-lives, the amount remaining can be calculated as follows: starting with 2 mg, after the first 3 hours (one half-life), 1 mg remains, and after the next 3 hours (the second half-life), 0.5 mg remains. Therefore, after 6 hours, 0.5 mg of Cu-61 would remain from the original 2 mg sample.
How much Cu-61 would remain from a 2 mg sample after 9 hours?
To determine how much Cu-61 remains after 9 hours, we need to know its half-life. Cu-61 has a half-life of about 3.33 hours. After 9 hours, which is approximately 2.7 half-lives, we can use the formula ( \text{Remaining mass} = \text{Initial mass} \times \left( \frac{1}{2} \right)^{n} ), where ( n ) is the number of half-lives. Thus, ( 2 , \text{mg} \times \left( \frac{1}{2} \right)^{2.7} ) yields approximately 0.31 mg of Cu-61 remaining.
