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Q: What is he average of 96 100 and 92?

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It is: (96+100+92)/3 = 96

To find the average of a set of numbers:1. sum up the numbers92 + 96 + 94 = 2822. divide the sum by the total number of numbers in the set282 / 3 = 9494 is the average.

88

Y / 6 = 92 92 * 6 = Y 92 * 6 = 552 90 + 98 + 96 + 94 + 85 = 463 552 - 463 = 89 Answer: 89

88 because you're taking 4 away each time.

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It is: (96+100+92)/3 = 96

96

88/92 * 100 = 96% ====

92

The median of 88, 92, 96, 99, and 100 is 96 because median pretty much means middle and the middle number is 96.

4x23=92 and 4x24=96.Hence 92 and 96.

55 + 82 + 92 + 78 + 100 + 96 + 78 = 581

92 96/100 = 92 24/25

80, 84, 88, 92, 96, 100

If they are all treated equally, you are averaging a 92.

Since the difference of any two consecutive numbers (the common difference) is 4 (a constant), then this sequence is an arithmetic sequence. Let's take a look at this sequence: t1 = 100 t2 = t1 - 4 = 100 - 4 = 96 t3 = t2 - 4 = 96 - 4 = 92 t4 = t3 - 4 = 92 - 4 = 88 Thus, the formulas t1 = 100 and tn = t(n-1) - 4 gives a recursive definition for the sequence 100, 96, 92, 88.

(100+65+93+84+90+96) ÷ 6 = 88 is the average

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