The last digit of a number raised to a power can be determined by finding a pattern in the units digits of the number's powers. For 2 raised to the power of 1997, the units digit will follow a pattern of 2, 4, 8, 6. Since 1997 is one less than a multiple of 4, the last digit will be 8.
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Ah, what a happy little question! When we have 2 raised to the power of 1997, we find that the last digit is 6. Isn't that just a lovely little detail to discover? Just like adding a touch of paint to a canvas, mathematics can reveal beauty in unexpected places.
Honey, the last digit in 2 to the power of 1997 is 6. You can thank me later for doing the math for you. Now go impress your friends with that little nugget of information.
To find the unit digit of 2 raised to the power of 40, we can observe a pattern. The unit digit of powers of 2 cycles in a pattern: 2, 4, 8, 6. Since 40 is a multiple of 4, the unit digit of 2^40 will be the fourth number in the pattern, which is 6. Thus, the unit digit of 2^40 is 6.
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The unit digit of 3127173 is the unit digit of 7173. The other digits of 3127 are multiples of 10 and so they cannot contribute to the unit digit. Now the unit digits of the powers of 7 are Power -- Unit digit 0 -- 1 1 -- 7 2 -- 9 3 -- 3 4 -- 1 and you are back into the loop (of 1-7-9-3). So, you only need consider 7 to the power 173 modulo 4. That is, the remainder when 173 is divided by 4. 173 = 1 mod 4 So the unit digit of 3127173 is the same as the unit digit of 7173 which is the unit digit of 71 which is 7.
it is unit for one and units for 2 or more
if you round to nearest unit, it is 3.