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What is ln1?

Updated: 4/28/2022
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12y ago

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its 0.

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Q: What is ln1?
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What is the derivative of ln 1 divided by 1-x?

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Who ln1 equals 0?

If you mean why, that is because e1 = 0. Remember that logarithm is the inverse operation to exponentiation.


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What is the derivative of ln1 divided by x?

Given y=ln(1/x) y'=(1/(1/x))(-x-2)=(1/(1/x))(1/x2)=x/x2=1/x Use the chain rule. The derivative of ln(x) is 1/x. Instead of just "x" inside the natural log function, it's "1/x". Since the inside of the function is not x, the derivative must be multiplied by the derivative of the inside of the function. So it's 1/(1/x) [the derivative of the outside function, natural log] times -x-2=1/x2 [the derivative of the inside of the function, 1/x] This all simplifies to 1/x So the derivative of ln(1/x) is 1/x


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